In a Fibonacci sequence, sum of two successive terms gives the third term....
here is the Fibonacci sequence:
0,1,1,2,3,5,8,13,21,34,55,89,144........
General formula to generate a Fibonacci sequence is """Fn= Fn-1 + Fn-2"""
To check whether a number is Fibonacci or not follow the following steps:
1) Get the number as input from user.
2) Fix the first two numbers of sequence as 0 and 1.
3) put a sentinel loop with upper limit being the input number.
4)in the body of loop generate the next number in sequence in each iteration and continue swapping the values as follows:
a=0
b=1
next=a+b
while (next< input)
a=b
b=next
next=a+b wend
5) lastly when program exits the loop compare the last number of sequence with the input number
if they are equal then number is Fibonacci otherwise not.
otherwise the last term of sequence will be less than the input number.
first we write start and then read number and after that check the number is totaly divide by 2 or not if number is totally divide by 2 then number is even else number is odd.
#include<iostream.h> #include<conio.h> void main() { long int n,a=0,b=1; cout<<"dear user Enter number as u wish"; cin>>n; while(n>0) { c=a+b; cout<<"c<<"\t\t"; a=b; b=c; } getch(); }
echo "Program to check even or odd number"echo "Enter a number"read na=`expr $n % 2`if [ $a -eq 0 ] ; then #Semicolon is most important for Executing ifelse statementsecho "It is an even number"elseecho "It is an odd number"fi
Algorithm Step1: Read A, B, C Step2: If A > B is True, then check whether A > C, if yes then A is greatest otherwise C is greatest Step3: If A > B is False, then check whether B > C, if yes then B is greatest otherwise C is greatest Give the Flowchart Answer
class Fibonacci { public static void main(String args[]) { System.out.println("enter the number upto u want"); int number=Integer.parseInt(args[0]); int a=0,b=1,c=0; System.out.print(a+" "+b); for(int i=1;i<=number;i++) { c=a+b; System.out.print(c+" "); a=b; b=c; } } } the number are given to the run time where are print the series eg: 5 0 1 1 2 3 5 8 13................
45
It is called a Fibonacci number sequence! 1,1,2,3,5,8,13,21...
Type your answer here... i think we should first enter 1 number then check it
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8086 assembly language program to check wether given number is perfect or not
Avogadro's number is a constant. Therefore only one number is equal to Avogadro's number.
write a program in C to check whether a given number is apalindrome or not
The Fibonacci sequence.
Fibonacci is most famous for his description of the number sequence, which in the 19th century was given the name 'Fibonacci numbers' . The sequence is made by starting with two ones, and adding them up, then to make every new term, the previous two terms need to be added together.
Is the last digit 2, 4, 6, 8 or 0? If yes, it's even, else odd.
If it is even
4 Fibanocci numbers are each the sum of the 2 previous numbers, i.e. 1,1,2,3,5,8 Thus 4 is the first one missing By modern definition, the above response is incorrect - 0 (zero) is both positive (it is defined as such) and not in the Fibonacci set. This answer is given based on a slight assumption, there cannot be a "first number" on a number line. The lowest number that is positive and not within the set of Fibonacci numbers (as inferred as the true meaning of your question) is zero.