int n,m,rem;
...
n=76;
m=19;
rem=n%m;
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Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.
#include<iostream.h> #include<conio.h> void main() { int a, b, c; clrscr(); cout<<"enter the two numbers"; cin>>a; cin>b; c=a+b; cout<<"Addition of two numbers="<<c; getch(); }
public int findSum(int n1, int n2) { return n1 + n2; }
#include<iostream> int main() { std::cout << "Enter two numbers: "; double a, b; std::cin >> a >> b; // note: error handling omitted for brevity! std::cout <<"The product of " << a << " and " << b << " is " << a*b << '\n'; }
$vi sum.sh echo "enter the 1st no." read num1 echo "enter the 2nd no." read num2 sum= 'expr $num1 + $num2' echo "sum of the numbers is $sum"