Write a program to input the square matrix and display the sum of diagonal elements?

Answer 1

#include<iostream>

#include<random>

#include<time.h>

int main()

{

std::default_random_engine generator ((unsigned)time(0));

std::uniform_int_distribution<int> distribution (1,9);

std::cout << "Array:\n" << std::endl;

int a[3][3];

for (size_t r=0; r!=3; ++r)

{

for (size_t c=0; c!=3; ++c)

{

a[r][c] = distribution (generator);

std::cout << a[r][c] << '\t';

}

std::cout << std::endl;

}

std::cout << std::endl;

int diagonal=0, anti_diagonal=0;

for (size_t i=0; i!=3; ++i)

{

diagonal += a[i][i];

anti_diagonal += a[2-i][i];

}

std::cout << "Diagonal sum : " << diagonal << std::endl;

std::cout << "Anti-diagonal sum : " << anti_diagonal << std::endl;

}

Answer 2

#include<iostream.h>

#include<conio.h>

void main()

{ int a=0,b=0,i,j,s,c[10][10]; //initialising matrix

cout<<"Enter size of square of Matrix \n";

cin>>s;

cout<<"Enter Values into Matrix of side(s) "<<s<<"\n";

for(i=0; i<s; i++) // Input Matrix

{ for(j=0; j<s; j++)

{ cin>>c[i][j]; }

}

cout<<"\nThe Given Matrix is\n"; // Output MAtrix

for(i=0; i<s; i++)

{ cout<<"\n"; for(j=0; j<s; j++)

{ cout<<c[i][j]; }

}

cout<<"\n";

for(i=0; i<s; i++) // Loop to add elemnts below main diagonal

{ for(j=0; j<s; j++)

if(i>j) a + = c[i][j]; }

for(i=0; i<s; i++) // Loop to add elements above main diagonal

{ for(j=0; j<s; j++)

if(i<j) b + = c[i][j]; }

cout<<"\nSum of elements above the main diagonal is : "<<b;

cout<<"\nSum of elements below the main diagonal is : "<<a

getch();

}

Answer 3

#include<conio.h>

#include<stdio.h>

void main()

{

int a[4][4],i,j,sum=0;

clrscr();

printf("enter 4*4 marks\n");

for(i=0;i<4;i++)

{

for{j=0;j<4;j++)

{

scanf("%d.&a[i][j]);

}

}

for

(i=0;i<4;i++)

{

sum=sum+a[i][j];

}

printf("sum of diagonal1=%d,sum);

sum=0;

for(i=0;i<4;i++)

{

sum+sum+a[i][3-1];

}

printf("\n sum of diagonal2=%d"sum);

getch();

}