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It depends on whether you count chocolate on top and strawberry on bottom as different than strawberry on top and chocolate on bottom.

If you want those to be the same, you use 31 choose 2, which is the number of combinations of two items you can have with 31 available items. To calculate this, you use 31! /2!(31-2)! =31x15

If you want those to be different, you'll use permutations instead. This would be 31!/(31-2)! = 31x30

See this website for more information: mathforum org

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