Assuming the 52 cards are all different, the first card can be any of the 52, the second card can be any of the remaining 51, and the third card can be any of the remaining 50, so there are 52x51x50 different three card hands possible.
2,560
A suit contains 13 cards of the same kind. 4 cards may be choosen out of 13 in 13C4 (715) ways. There are 4 suits. Therefore, the number of possible hands for getting 4 cards of the same suit is 4 x 13C4 = 4 x 715 = 2,860.
If the cards are all different then there are 13C7 = 1716 different hands.
4(13c4)(39c1) = (4)(715)(39)=1,11,540
13 x 12 x 11 x 49 x 48 13 x 12 x 11 because there are 13 possible cards for any given suit, then 12 more of the same suit, then 11 more for the same suit. At this point, you have 49 cards left, then 48. So there are 4,036,032 possible hands like that.
23
In poker, there are 2,598,960 possible hands that can be dealt.
The odds of getting 4 cards in any particular suit (for example, hearts) would be:1/4*1/4*1/4*1/4=1/256.The odds of getting 4 cards of the same suit (any suit) would be 4x greater:1/256*4=1/64Because it doesn't matter what the last card is, the probability is 1/64.
In poker, there are 2,598,960 possible starting hands.
If the hand must contain three 8's and to cards that are not 8's - the total number of possibilities is 2801.
In poker, there are a total of 1,326 possible starting hands.
three