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The odds of getting 4 cards in any particular suit (for example, hearts) would be:

1/4*1/4*1/4*1/4=1/256.

The odds of getting 4 cards of the same suit (any suit) would be 4x greater:

1/256*4=1/64

Because it doesn't matter what the last card is, the probability is 1/64.

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Q: How many possible hands are there for getting 4 cards in the same suit with the other cards in any other random suit?
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How many possible hands are there for getting 4 Cards of the same suit and 1 random card?

4(13c4)(39c1) = (4)(715)(39)=1,11,540


How many possible hands are there for getting 3 Cards of the same suit and 2 random cards?

13 x 12 x 11 x 49 x 48 13 x 12 x 11 because there are 13 possible cards for any given suit, then 12 more of the same suit, then 11 more for the same suit. At this point, you have 49 cards left, then 48. So there are 4,036,032 possible hands like that.


What is the probability of getting 9 cards of the same suit in one hand out of 52 cards?

Asssuming you mean in a 13 card hand, to get exactly nine cards in a suit, there are 4 x C(13,9) x C(39,4) possible hands out of C(52,13) total hands. That is 4 x 58,809,465 / 635,013,559,600 = 0.000370445412454, or about 1 in 2700.


What are the chances of a royal flush on the flop and the turn in Texas hold 'em?

There are 2,598,960 possible five-card hands. There are 4 combinations of royal flushes in 5 cards. Therefore, the odds are 649,739:1. There are 20,358,520 possible six-card hands. There are 188 combos of royal flushes in 6 cards. Therefore, the odds are 108,290:1.


Consider a standard deck of 52 cards how many different four cars hands have no red cards?

26 of the 52 cards are black. For each of those cards, the second card in your hand may not be the same card, but it may be any of the 25 remaining ones. The third card, likewise, can not be the first two, but can be any of the 24 remaining. For a four card hand that's 26 * 25 * 24 * 23 = 358800 possible hands However, that number includes sets that are effectively duplicates (1,2,3,4 and 4,3,2,1 are both accounted for in that number, but for our purposes those are the same hand). We can arrange each set of cards 4 * 3 * 2 * 1 = 24 ways. So to remove those possibilities we take 358800/24 = 14950 possible hands of all black cards.

Related questions

How many possible hands are there for getting 4 Cards of the same suit and 1 random card?

4(13c4)(39c1) = (4)(715)(39)=1,11,540


How many possible hands are there for only getting 4 cards that make a straight?

2,560


How many possible hands are there for getting 3 Cards of the same suit and 2 random cards?

13 x 12 x 11 x 49 x 48 13 x 12 x 11 because there are 13 possible cards for any given suit, then 12 more of the same suit, then 11 more for the same suit. At this point, you have 49 cards left, then 48. So there are 4,036,032 possible hands like that.


How many possible hands are there for getting 4 cards of the same suit?

A suit contains 13 cards of the same kind. 4 cards may be choosen out of 13 in 13C4 (715) ways. There are 4 suits. Therefore, the number of possible hands for getting 4 cards of the same suit is 4 x 13C4 = 4 x 715 = 2,860.


How many 7 card hands are possible with a 13 cards deck?

If the cards are all different then there are 13C7 = 1716 different hands.


What is the probability of getting 9 cards of the same suit in one hand out of 52 cards?

Asssuming you mean in a 13 card hand, to get exactly nine cards in a suit, there are 4 x C(13,9) x C(39,4) possible hands out of C(52,13) total hands. That is 4 x 58,809,465 / 635,013,559,600 = 0.000370445412454, or about 1 in 2700.


How many possible hands are there for getting 3 cards of the same suit?

Assuming the 52 cards are all different, the first card can be any of the 52, the second card can be any of the remaining 51, and the third card can be any of the remaining 50, so there are 52x51x50 different three card hands possible.


How many possible hands can be dealt from a standard deck of cards in Texas hold em?

23


Is it possible for a three pair in poker?

Poker hands consist of only five cards, three pair is impossible.


Can you have a run of four in Texas holdem?

All poker hands consist of five cards. In Texas Holdem, you can use two, one or none from your hand and three, four or five of the community cards (the "board"). Because all hands are five cards, it is not possible to have a four-card run, or straight. It counts for nothing.


What are the chances of a royal flush on the flop and the turn in Texas hold 'em?

There are 2,598,960 possible five-card hands. There are 4 combinations of royal flushes in 5 cards. Therefore, the odds are 649,739:1. There are 20,358,520 possible six-card hands. There are 188 combos of royal flushes in 6 cards. Therefore, the odds are 108,290:1.


Does a straight beat three pair in Texas hold-em?

It is not possible to have 3 pair in a game of Texas hold'em because you can only use 5 cards out of 7 and 3 pair uses 6. A straight of 5 cards is a valid hand. The full list of Poker Hand Rankings contains 10 hands.