Assuming it is a rectangle, 56.232 imperial gallons
5.07 inches
The area of a parallelogram with a base of 9 inches and a height of 10 inches is 90 square inches.
The perpendicular height is 6 inches and the slant height is 6.7082 inches.
The height of an object given a length of 50 inches.
The height of a Quagga was 52 inches.
If it is a right cone, then by Pythagoras,(Slant height)2 = 52 + 11 = 25 + 1 = 26 inches2So slant height = sqrt(26) inches = 5.099 inches = 5.10 inches (to 2 dp)If it is a right cone, then by Pythagoras,(Slant height)2 = 52 + 11 = 25 + 1 = 26 inches2So slant height = sqrt(26) inches = 5.099 inches = 5.10 inches (to 2 dp)If it is a right cone, then by Pythagoras,(Slant height)2 = 52 + 11 = 25 + 1 = 26 inches2So slant height = sqrt(26) inches = 5.099 inches = 5.10 inches (to 2 dp)If it is a right cone, then by Pythagoras,(Slant height)2 = 52 + 11 = 25 + 1 = 26 inches2So slant height = sqrt(26) inches = 5.099 inches = 5.10 inches (to 2 dp)
52 meters = 2,047.24 inches.
52 inches = 0.0013208 kilometres
It depends on what 52 is.
yes
There are 1.4444442987442 yards in 52 inches. There are 4 feet and 4 inches(4.33333301544189 feet) in 52 inches.
52 inches !
52 inches is 1.32 meters.
20.8 inches
There are 20.47244094 inches in 52 centimeters. 52 centimeters x 1 inch/2.54 centimeters = 20.47244094 inches 1 inch = 2.54 centimeters
52 inches.