The volume of the similar solid would be 16M squared.
Yes.
If you imagine a square-based pyramid sitting on its base, there will be the four corners of the square, plus the top: a square-based pyramid has five corners.
Volume of a squared based pyramid: 1/3*base area*height
SA equals pi times the radius squared
The surface area is length times width plus length. Then you find the square root of the width divided by two and then squared. You add this to the height squared plus the width. The width is multiplied by the square root of 1/2 squared plus the height squared.
Triangular Pyramid, Squared Pyramid, Pyramid
A square-pyramid
1/2(p)(sh) ~which means~ 1/2 x perimeter x slant height slant height= pathagorean theory= c squared= a squared+b squared
5
h
8
Use the Pythagorean theorem (a-squared + b-squared = c-squared) Remember, the hypotenuse is c.
In a regular pyramid, the distance from the vertex to the midpoint of an edge of the base can be calculated using the Pythagorean theorem. This distance is equal to the height of the pyramid squared plus the square of half the length of the base edge. The formula can be expressed as (d = \sqrt{h^2 + \left(\frac{b}{2}\right)^2}), where (h) is the height of the pyramid and (b) is the length of the base edge. Thus, the distance varies depending on the specific dimensions of the pyramid.
Five.
5 faces
A squared + b squared = c saqared (a is a leg), (b is a a leg), (c is a leg)
Yes.