a convex polygon
concave polygon
Exterior angle 60 therefore interior angle at that point 180 - 60 = 120 Figure is a hexagon (Internal angles = 12 - 4 right angles or 720 degrees) ?All polygons have exterior angles that sum to 360 degrees. An exterior angle of a polygon is found by "extending" one of the sides and measuring the angle between that extension and the "next" side. As the polygon in question is regular and has exterior angles of 60 degrees, it has 360/60 sides, or 6 sides.
angle BLD is 72 degrees.
Polygon
A point that two sides of a polygon have in common is called a vertex. Each regular polygon has an equal number of sides as vertices.
It is concave.
concave polygon
convex
The exterior angle of a polygon is formed by extending one side of the polygon at a vertex. The sum of the angles around a point is always 360 degrees, which includes the exterior angle and the adjacent interior angle. Since the interior angle and the exterior angle at a vertex are supplementary (they add up to 180 degrees), the exterior angle itself can be thought of in the context of multiple vertices around a point, leading to the total sum of all exterior angles of a polygon being equal to 360 degrees, regardless of the number of sides.
Exterior angle 60 therefore interior angle at that point 180 - 60 = 120 Figure is a hexagon (Internal angles = 12 - 4 right angles or 720 degrees) ?All polygons have exterior angles that sum to 360 degrees. An exterior angle of a polygon is found by "extending" one of the sides and measuring the angle between that extension and the "next" side. As the polygon in question is regular and has exterior angles of 60 degrees, it has 360/60 sides, or 6 sides.
You divide 360 by 16. For the exterior angle of any regular polygon, just divide 360 by the number of sides because the exterior angle of all regular (possibly all convex polygons, but I'm not sure on that point) add up to 360 degrees. The answer is: 22.5 degrees.
Then the point is not outside the polygon...?
Suppose the square is ABCD. Draw the diagonal AC.Mark one point on the diagonal, P (not the midpoint of AC), at a distance x from A. Mark another point, Q, also on the diagonal, at the same distance from C.Then,PBQD is a rhombus,ABPD and BCDQ are arrowheads.Suppose the square is ABCD. Draw the diagonal AC.Mark one point on the diagonal, P (not the midpoint of AC), at a distance x from A. Mark another point, Q, also on the diagonal, at the same distance from C.Then,PBQD is a rhombus,ABPD and BCDQ are arrowheads.Suppose the square is ABCD. Draw the diagonal AC.Mark one point on the diagonal, P (not the midpoint of AC), at a distance x from A. Mark another point, Q, also on the diagonal, at the same distance from C.Then,PBQD is a rhombus,ABPD and BCDQ are arrowheads.Suppose the square is ABCD. Draw the diagonal AC.Mark one point on the diagonal, P (not the midpoint of AC), at a distance x from A. Mark another point, Q, also on the diagonal, at the same distance from C.Then,PBQD is a rhombus,ABPD and BCDQ are arrowheads.
angle BLD is 72 degrees.
A point and most of the time meets, a polygon is a circle thing that meets at some point!
Polygon
An exterior point, in the context of geometry and topology, refers to a point that lies outside a given set or region. Specifically, it is not contained within the boundaries of the set and has a neighborhood that does not intersect with the set. In simpler terms, if you can draw a small circle around the exterior point without touching the set, then that point is considered an exterior point.