let the vertex angle be x degrees, then the base angle is x + 9 degrees. Since in a triangle the sum of the angle is 180 degrees, and the base angles in an isosceles triangle are congruent, we have:
x + 2(x + 9) = 180
x + 2x + 18 = 180
3x + 18 = 180 subtract 18 to both sides
3x = 162 divide by 3 to both sides
x = 54
Thus the vertex angle is 54 degrees.
an isosceles triangle can have any vertex angle less than 180 and greater than 0, as long the other two angles are equal. an isosceles triangle with a vertex of 179 degrees would just have the other two angles be 0.5 degrees. A right triangle with matching angles (both 45 degrees) would be both a right triangle and isosceles triangle.
If that '56' has units of 'degrees', then the vertex angle is 68 degrees.
30o
The base angles will have equal angles of 50 degrees
Each base angle is 62.5 degrees
56 degrees
90 degrees. This is an isosceles right triangle, standing on its hypotenuse.
20 degrees
If your "53" is in degrees, then the vertex angle is 74 degrees.
The vertex angle of an isosceles triangle is equal to the measure of each of its base angles. Therefore, if one of the base angles measures 42 degrees, then the vertex angle also measures 42 degrees.
an isosceles triangle can have any vertex angle less than 180 and greater than 0, as long the other two angles are equal. an isosceles triangle with a vertex of 179 degrees would just have the other two angles be 0.5 degrees. A right triangle with matching angles (both 45 degrees) would be both a right triangle and isosceles triangle.
57.5 degrees
130 degrees is the measure of the base angles of an isosceles triangle whose vertex has a measure of 50 degrees.
Vertex angle = 180 - 2(62) = 56 degrees
80 degrees
If that '56' has units of 'degrees', then the vertex angle is 68 degrees.
(180 - 38)/2 = 71 degrees (base angles of an isosceles triangle are congruent).