A circular tank is 12 meter in diameter and 7.5 meter in height. how much water does it hold when half full?
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3697 Gallons @ 80% of wall height
The answer two this question depends on two factors: - Determining the volume of the shape in question. - Determining the weight the of the matter the object is composed of. For example a 3 dimensional square that is 1 meter in length, 1 meter in width and 1 meter in height is filled with water. To determine the weight of the water: - The volume formula for a rectangle is volume = length X width x height; In our case volume = 1 x 1 x 1 = 1 m^3 (one meter cubed) - the wight of water is 1 per cubic meter. Therefore 1 m^3 of water weighs 1 kg.
This is a clever problem. It sounds really complicated, but that's only becauseit's actually two simple problems rolled into one.The two problems are:1). Volume of a rectangular prism2). Volume of a cylinderBefore we get started, let's make sure you remember the formulas for both ofthose volumes:1). Rectangular prism . . . V = (length) x (width) x (height)2). Cylinder . . . Volume = (pi) x (radius)2 x (height)The attack is:-- Figure out the volume of the water that rained onto the roof.-- Realize that the same volume poured into the cylindrical tub.-- Figure out how deep that much water fills the cylinder.At this point, the hard part is done! The problem is as good as solved.-- 1.2 cm of rain falls on the 10m x 5.5m rectangular roof. How much water is sitting on the roof ?Volume = L x W x H = (10m) x (5.5m) x (0.012 m) = 0.66 cubic meter of water-- Now pour that water into the cylinder with 3m diameter. How deep is it ?Volume = (pi) x (radius)2 x (height) .We need to find the height, so solve this formula for the height.Divide each side of equation by (pi) x (radius)2 :Height = Volume / (pi) x (radius)2The volume is the 0.66 m3 that poured off of the roof.The radius is 1/2 of the diameter = 1.5m .So Height = (0.66)/(pi) x (1.5)2 = 0.09337 meter = 9.337 cm.
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Standard meter will suffice, need to know pressure from meter to house. Size pipe appropriately for gas pressure coming into house X distance to water heater. Gas company or plumber should be able to help with this calculation.