3697 Gallons @ 80% of wall height
Assuming it is a rectangle, 56.232 imperial gallons
If the pond is uniformly 6-feet deep it would contain about 1,955,109 gallons of water.
A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.
Here is my take: 1 gallon of water equals 231 cubic inches 1 square foot, 1 inch tall equals 144 cubic inches (12"x12"X1") 1 square foot needs 0.624 gallons to equal 1 inch of cover (144 cubic inched divided by 231 cubic inches) 16 square feet would require 9.975 gallons of water to be covered 1 inch deep. (16*0.624) **Runsky**
Calculate the volume (cubic ft capacity) of the pool and multiply by the number of gallons per cubic foot. To calculate, the formula is V = (Pi x R²)(H) where Pi = 3.1416, R² is the radius multiplied by itself (radius is one-half of the diameter), and H is the height or depth. There are 7.481 gallons of water in 1 cubic foot. V = (3.1416 x 12²)(4) = (3.1416 x 144)(4) = (242.3904)(4) = 1809.5616 cu ft 1809.5616 x 7.481 = 13,537.33 gallons
489.76 gallons of water.
66 gallons
Exactly 35.2332 gallons, but 36 to be safe.
16.32 US gallons.16.32 US gallons.16.32 US gallons.16.32 US gallons.
Is the pool a circle? Do you want US gallons, or Imperial gallons?
Volume = (pi) R2 L = (pi) (30)2 (12) = 10,800 pi = 33,929.2 cubic inches = 146.88 gallons (rounded)
885 gallons.
Depends on the depth. If it is 4 feet deep and it is cicular with a diameter of 24 feet then you have approx. 13,553 gallons of water. If it is 3 feet deep then you have approx. 10,152 gallons of water.
Assuming the dimensions given are inside dimensions, the cylinder will hold 55.75 gallons - less if the dimensions given are outside dimensions.
29.45 cubic feet or 183.45 US gallons.
This pool can hold a maximum of about 18,420 gallons of water.
21.76 US gallons of water.