If the pond is uniformly 6-feet deep it would contain about 1,955,109 gallons of water.
A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.
Here is my take: 1 gallon of water equals 231 cubic inches 1 square foot, 1 inch tall equals 144 cubic inches (12"x12"X1") 1 square foot needs 0.624 gallons to equal 1 inch of cover (144 cubic inched divided by 231 cubic inches) 16 square feet would require 9.975 gallons of water to be covered 1 inch deep. (16*0.624) **Runsky**
Calculate the volume (cubic ft capacity) of the pool and multiply by the number of gallons per cubic foot. To calculate, the formula is V = (Pi x R²)(H) where Pi = 3.1416, R² is the radius multiplied by itself (radius is one-half of the diameter), and H is the height or depth. There are 7.481 gallons of water in 1 cubic foot. V = (3.1416 x 12²)(4) = (3.1416 x 144)(4) = (242.3904)(4) = 1809.5616 cu ft 1809.5616 x 7.481 = 13,537.33 gallons
That all depends on how deep the 530 sq ft area is
489.76 gallons of water.
About 3,983 gallons.
846 gallons of water for a cylinder 24 feet in diameter and three inches deep/long.
Exactly 35.2332 gallons, but 36 to be safe.
Is the pool a circle? Do you want US gallons, or Imperial gallons?
Depends on the shape of the pool.
16.32 US gallons.16.32 US gallons.16.32 US gallons.16.32 US gallons.
I assume you mean 5 foot diameter AND 6 inches deep: 9.8125 cu.ft. = 73.3975 gallons
A round, 16' diameter 4' deep pool has a capacity of about 6,016 gallons of water.