3697 Gallons @ 80% of wall height
Assuming it is a rectangle, 56.232 imperial gallons
If the pond is uniformly 6-feet deep it would contain about 1,955,109 gallons of water.
A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.
Here is my take: 1 gallon of water equals 231 cubic inches 1 square foot, 1 inch tall equals 144 cubic inches (12"x12"X1") 1 square foot needs 0.624 gallons to equal 1 inch of cover (144 cubic inched divided by 231 cubic inches) 16 square feet would require 9.975 gallons of water to be covered 1 inch deep. (16*0.624) **Runsky**
To calculate the volume of water in a round pool, you can use the formula for the volume of a cylinder: V = πr^2h, where r is the radius and h is the height. In this case, the radius is half the diameter, so it is 12 feet. Plugging in the values, we get V = π(12^2)(4) = 576π cubic feet. To convert cubic feet to gallons, you would multiply by 7.48, the number of gallons in a cubic foot, so the pool would hold approximately 4309 gallons of water.
489.76 gallons of water.
66 gallons
Exactly 35.2332 gallons, but 36 to be safe.
16.32 US gallons.16.32 US gallons.16.32 US gallons.16.32 US gallons.
Is the pool a circle? Do you want US gallons, or Imperial gallons?
885 gallons.
Depends on the depth. If it is 4 feet deep and it is cicular with a diameter of 24 feet then you have approx. 13,553 gallons of water. If it is 3 feet deep then you have approx. 10,152 gallons of water.
Assuming the dimensions given are inside dimensions, the cylinder will hold 55.75 gallons - less if the dimensions given are outside dimensions.
29.45 cubic feet or 183.45 US gallons.
This pool can hold a maximum of about 18,420 gallons of water.
21.76 US gallons of water.
17,204 gallons.