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Q: How many gallons of water does a pool 16 ft in diameter and 42 inches deep hold?

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If the pond is uniformly 6-feet deep it would contain about 1,955,109 gallons of water.

A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.

Here is my take: 1 gallon of water equals 231 cubic inches 1 square foot, 1 inch tall equals 144 cubic inches (12"x12"X1") 1 square foot needs 0.624 gallons to equal 1 inch of cover (144 cubic inched divided by 231 cubic inches) 16 square feet would require 9.975 gallons of water to be covered 1 inch deep. (16*0.624) **Runsky**

Calculate the volume (cubic ft capacity) of the pool and multiply by the number of gallons per cubic foot. To calculate, the formula is V = (Pi x R²)(H) where Pi = 3.1416, R² is the radius multiplied by itself (radius is one-half of the diameter), and H is the height or depth. There are 7.481 gallons of water in 1 cubic foot. V = (3.1416 x 12²)(4) = (3.1416 x 144)(4) = (242.3904)(4) = 1809.5616 cu ft 1809.5616 x 7.481 = 13,537.33 gallons

That all depends on how deep the 530 sq ft area is

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489.76 gallons of water.

About 3,983 gallons.

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846 gallons of water for a cylinder 24 feet in diameter and three inches deep/long.

465 gallons

Exactly 35.2332 gallons, but 36 to be safe.

Is the pool a circle? Do you want US gallons, or Imperial gallons?

Depends on the shape of the pool.

16.32 US gallons.16.32 US gallons.16.32 US gallons.16.32 US gallons.

I assume you mean 5 foot diameter AND 6 inches deep: 9.8125 cu.ft. = 73.3975 gallons

885 gallons.

A round, 16' diameter 4' deep pool has a capacity of about 6,016 gallons of water.

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