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The figure could be a rectangle with length 4.73 and width 1.27(2dp).
Area (A) of a rectangle = Length (L) x Width (W) = 6 : Then W = 6/L
Perimeter = 2 (L + W) = 12 : substituting for W then :-
2(L + 6/L) = 12 : 2L + 12/L = 12 : 2L2 - 12L + 12 = 0
Solving for a quadratic equation gives L = (12 ± √48) ÷ 4 = 3 ± √3 = 3 ± 1.73 (2dp)
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