A girl 1.2 m in height is 25 m away from a tower 18 m high. What value is the angle of elevation of the top of the tower from her eyes?
Angle of elevation: tangent-1*(16.8/25) = 34 degrees rounded
34°
You cannot. An exterior angle of a decagon can have any value.
The value of sin A is 5.82 and the actual angle is 19.47 degees
No. An obtuse angle has a measure in the range (90, 180) degrees. The angle in question is greater than the maximum value for an obtuse angle.
That will depend on the size of the original angle of and what kind of shape it is which has not been given.
90
When surveying using a "level" instrument , the "level" instrument is set-up and adjusted to level by adjusting the screws. When surveying you have an instrument person and a rod person. When trying to find the height of the instrument, the rod person places there rod over a "known" elevation, either a benchmark or a temporary benchmark that has a known elevation. To get the height of the instrument, you need to "shoot" the level to the rod person holding the rod on the known elevation, this is called the "Backsight". This elevation will be read by the instrument person, and recorded in the survey field book. This value backsight elevation will then be added to the known elevation of the benchmark or the temporary benchmark, to get the height of instrument. HI = known elevation + BS Height
Actually, the question is unanswerable. You need to at least know the height of one object - either the ship, or the cliff height, or the distance between the cliff to the water, and the cliff to the boat. I don't know if it can be answered, it doesn't give enough information one would have to have one distance value or speed value. I think at least.
The height of a boy that casts a 4 foot long shadow depends on the angle of the sun. A tangent can be used to calculate his height if we know the angle of the sun using the equation: Height = shadow length x tangent of the angle of the sun. Using a calculator, it is easy to get the value of the tangent for any angle and then complete the equation.
Max height H = u2 sin2@ / 2g So as we increase the angle of projection, then max height too increases and its value will be just u2/2g when it is projected vertically upwards ie @ = 90 deg
The two triangles shown are similar triangles. Numerically, the ratio computed by dividing the length of any side of tower triangle by the length of the corresponding side of the walking stick (similar) triangle will be the same value. Therefore, when the length of the tower shadow is divided by the length of the walking stick shadow, that ratio will be the exactly same as the tower height divided by the walking stick height. (length of tower shadow)/(length of walking stick shadow) = (tower's height)/(walking stick height) tower's height = {(length of tower shadow)/(length of walking stick shadow)}*(walking stick height)
Use the tangent formula: tanx= opposite side {divided by} adjacent side 1) Divide the 2 sides I side. 2) See the "tanx"? Tan is a value. And x is a variable. To get x, the angle we are looking for, we must take the answer from 1) and go tan-1 on it (some calculators you hit tan, then 2nd function, others are the opposite). 3)You should have the value of x, the angle of elevation to the sun.
Angle a, by itself has no value. You must first assign a value to a to get the value of tan a.
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
If it's a right angle triangle then use Pythagoras' theorem to find the hypotenuse. If it's not then more information is needed such as an interior angle.
It depends on the mass of the object, the local value of acceleration of gravity, and the object's height above the elevation you're using for your zero-potential-energy reference level.
It depends on the mass of the object, the local value of acceleration of gravity, and the object's height above the elevation you're using for your zero-potential-energy reference level.
It depends on the mass of the object, the local value of acceleration of gravity, and the object's height above the elevation you're using for your zero-potential-energy reference level.