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Where the equation is ax2 + bx + c the roots are given by the solutions to :
(-b +/- sqrt(b2 - 4ac))/2a
So you would first input the values of a, b , and c, then calculate [d = b*b - 4*a*c], and then determine whether it is positive or negative. If it is positive [d>0, or d=0], then you can continue:
so the two roots of x are: (-b + sqrt(d))/2/a, and (-b - sqrt(d))/2/a.
If d < 0, then you need to calculate sqrt(-d) and then display -b/2/a as the real part, and +/- sqrt(-d)/2/a as the imaginary parts.
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How many roots does a quadratic equation?
2 roots
Write an algorithm to find the root of quadratic equation?
Write an algorithm to find the root of quadratic equation
What form is the solving for the roots of quadratic equations?
Using the quadratic equation formula or completing the square
What is the sum and product of roots of a quadratic equation?
the sum is -b/a and the product is c/a
What is a discriminant in a quadratic equation?
General form of a quadratic equation is: ax2+b+c = 0 The discriminant is: b2-4ac If the discriminant equals zero then there are two equal roots If the discriminant is greater than zero then there are two different roots If the discriminant is less than zero then there are no real roots
