The equation for the perimeter of a rectangle is 2x(a+b) where a is the length and b is the width. We can rewrite the question as the following:
2x(52+b) = 182
If both sides are divided by 2 we get:
52+b = 91
If we subtract 52 from both sides we get:
91 - 52 = 39.
Thus the width of the rectangle is 39 in.
Length = width + 2cm Width = Height - 4cm The sum of the length, width, and height is 546 cm Substitute the width term into the length equation, ((H -4) + 2) + (H - 4) + H = 546 Combining terms gives the following: 3H - 6 = 546 3H = 552 H = 184cm W = 184 - 4 = 180 cm L = 180 + 2 = 182 cm
Each side = sqrt (182 / 2) = sqrt (162) = 12.72792 metres
Answer: 182 ft² = 16.9083 m²
182
182 sq. meters = 1,959.032 sq. feet.
1.632m
Perimeter = 2*(L+W) = 2*(400+182) = 2*582 = 1164 units
Let the width be x:- 2(x+52) = 182 2x+104 = 182 Subtract 104 from both sides and then divide both sides by 2 to find the width:- x = 39 inches Check: 2(39+52) = 182 inches
perimeter 182 ft. area 1960 square ft.
It is 182 cm.
Let the length of a side of the square be S.Then the length of the rectangle = S + 9, and the width = S - 6As the areas are equal then, S2 = (S + 9)(S - 6) = S2 +3S - 54Thus, 3S = 54 : S = 18The length of a side of the square is 18 cm.Check : 182 = 324 : (18 + 9)(18 - 6) = 27 x 12 = 324
182 linear feet can be converted to (not too) any measurement of length or to area (if the width is known), or volume (if width and height are known).
Length = width + 2cm Width = Height - 4cm The sum of the length, width, and height is 546 cm Substitute the width term into the length equation, ((H -4) + 2) + (H - 4) + H = 546 Combining terms gives the following: 3H - 6 = 546 3H = 552 H = 184cm W = 184 - 4 = 180 cm L = 180 + 2 = 182 cm
12.92 square meters.
length = 36width = 18Ratio length : width36:18divide both sides by 182:1The ratio of length to width is 2 as to 1.
182 square feet. Just multiply length by width - the answer is the square footage.
Even if you knew how many sides the polygon has, you stillcould not calculate its perimeter with that much information.Examples:-- An equilateral triangle with area of 20 has perimeter of 20.3885 .-- A square with area of 20 has perimeter of 17.889(rounded).-- A rectangle with area of 20 can have any perimeter more than 17.889 .4 by 5 . . . . area = 20, perimeter = 182 by 10 . . . area = 20, perimeter = 241 by 20 . . . area = 20, perimeter = 42..etc.