Each side = sqrt (182 / 2) = sqrt (162) = 12.72792 metres
A square has 4 sides of equal length (say x). The diagonal length = x * (2)^0.5 = 1.414x, from Pythagorus's theorem. So, dividing the diagonal length by the square root of 2 will be the answer.
The length of the diagonal of a square with sides 5 is 5√2. This is because of the properties of a 45-45-90 triangle.
In a square, all sides are of equal length. The square root of the area will give you the length of a side. The square root of 9 sq meters is 3 meters.
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
Doesn't seem likely, does it? A diagonal 50 times the length of the sides? Diagonal = sqrt(252 + 252), ie sqrt 1250(!) which is 35.36 to the nearest hundredth.
A square has 4 sides of equal length (say x). The diagonal length = x * (2)^0.5 = 1.414x, from Pythagorus's theorem. So, dividing the diagonal length by the square root of 2 will be the answer.
A square with 2-inch sides has a diagonal of: 2.828 inches.
7.0711 (rounded)
As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.
8*sqrt(2) The diagonal of the square would be the hypotenuse of the right triangle formed by two of the sides of the square.
15.6977cm
The length of a diagonal of a square with sides equal to 1 = the square root of 2 Therefore any diagonal will always be in multiples of the square root of 2
The length of the diagonal of a square with sides 5 is 5√2. This is because of the properties of a 45-45-90 triangle.
Using Pythagoras' theorem the answer is equal to the square root of 2.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
It depends on 2.35m what: length of sides, diagonal, perimeter.
Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2