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How do you find the midpoint of a segment with the endpoints -4 -14 -22 9?
Points: (-4, -14) and (-22, 9) Midpoint: (-4-22)/2, (-14+9)/2 => (-13, -2.5)
What is the length of segment vs?
It is the distance between its endpoints of v and s
What is the length and midpoint of the line segment joining the points of -6 1 and 6 6?
Length = 13 units Midpoint = (0, 3.5)
The length of the blue line segment is 7 How long is the red line segment?
13
What undefined terms are needed to define a line segment?
13
What is the midpoint of the line segment whose endpoints are (-8 12) and (-13 -2)?
Endpoints: (-8, 12) and (-13, -2) Midpoint: (-10.5, 5)
A segment has endpoints at -13 19 and 4 -7 What is the x coordinate of the midpoint of that segment?
-4.5
The midpoint of the line segment whose endpoints are -8 12 and -13 -2?
Midpoint: (-10.5, 5)
What is the midpoint of the line segment whose endpoints are -8 12 and -13 -2?
The midpoint is the point (-10.5, 5) .
How do you find the midpoint of a segment with the endpoints -4 -14 -22 9?
Points: (-4, -14) and (-22, 9) Midpoint: (-4-22)/2, (-14+9)/2 => (-13, -2.5)
What is the midpoint of the line segment with endpoints -5.5 -6.1 and -0.5 9.1?
What is the location of the point on the number line that is 1/4 of the way from A=37 to B=13
What is the length of segment vs?
It is the distance between its endpoints of v and s
What is the perpendicular bisector equation of the line segment with endpoints of -1 -6 and 5 -8?
Endpoints: (-1, -6) and (5, -8) Midpoint: (2, -7) Slope: -1/3 Perpendicular slope: 3 Perpendicular bisector equation: y - -7 = 3(x -2) => y = 3x -13
What is the length and midpoint of the line segment joining the points of -6 1 and 6 6?
Length = 13 units Midpoint = (0, 3.5)
What is the midpoint of a segment whose endpoints are (-3-3) and (-13-13)?
It is [(3 + -13)/2, (3 + -13)/2] = [-10/2, -10/2] = (-5, -5)
What is the perpendicular bisector equation to the line segment of -1 -6 and 5 -8?
Points: (-1, -6) and (5, -8) Midpoint: (2, -7) Perpendicular slope: 3 Perpendicular bisector equation: y = 3x -13
Distance between 8 -13 and 1 -7 Midpoint between 8 -13 and 1 -7?
For the distance, use the Pythagorean formula. For the midpoint, take the average of the x-coordinates, and the average of the y-coordinates.
