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What is the midpoint of the line segment whose endpoints are (-8 12) and (-13 -2)?
Endpoints: (-8, 12) and (-13, -2) Midpoint: (-10.5, 5)
The midpoint of the line segment whose endpoints are -8 12 and -13 -2?
Midpoint: (-10.5, 5)
What is the midpoint of the line segment whose endpoints are -8 12 and -13 -2?
The midpoint is the point (-10.5, 5) .
Find the coordinates of the midpoint of the segment whose endpoints are H(8 13) and K(10 9).?
To find the midpoint of the segment with endpoints H(8, 13) and K(10, 9), use the midpoint formula: ( M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) ). Plugging in the coordinates, we get ( M = \left( \frac{8 + 10}{2}, \frac{13 + 9}{2} \right) = \left( \frac{18}{2}, \frac{22}{2} \right) = (9, 11) ). Therefore, the coordinates of the midpoint are (9, 11).
What is the perpendicular bisector equation of the line segment with endpoints of -1 -6 and 5 -8?
Endpoints: (-1, -6) and (5, -8) Midpoint: (2, -7) Slope: -1/3 Perpendicular slope: 3 Perpendicular bisector equation: y - -7 = 3(x -2) => y = 3x -13
A segment has endpoints at -13 19 and 4 -7 What is the x-coordinate of the midpoint of that segment?
End-points are (-13, 19) and (4, -7). The midpoint of the segment is (-4.5, 6). The X-coordinate is-4.5 we discuss about it.
What is the midpoint of the line segment whose endpoints are (-8 12) and (-13 -2)?
Endpoints: (-8, 12) and (-13, -2) Midpoint: (-10.5, 5)
The midpoint of the line segment whose endpoints are -8 12 and -13 -2?
Midpoint: (-10.5, 5)
What is the midpoint of the line segment whose endpoints are -8 12 and -13 -2?
The midpoint is the point (-10.5, 5) .
How do you find the midpoint of a segment with the endpoints -4 -14 -22 9?
Points: (-4, -14) and (-22, 9) Midpoint: (-4-22)/2, (-14+9)/2 => (-13, -2.5)
What is the midpoint of the line segment with endpoints -5.5 -6.1 and -0.5 9.1?
What is the location of the point on the number line that is 1/4 of the way from A=37 to B=13
What is the length of segment vs?
It is the distance between its endpoints of v and s
What is the perpendicular bisector equation of the line segment with endpoints of -1 -6 and 5 -8?
Endpoints: (-1, -6) and (5, -8) Midpoint: (2, -7) Slope: -1/3 Perpendicular slope: 3 Perpendicular bisector equation: y - -7 = 3(x -2) => y = 3x -13
What is the midpoint of a segment whose endpoints are (-3-3) and (-13-13)?
It is [(3 + -13)/2, (3 + -13)/2] = [-10/2, -10/2] = (-5, -5)
What is the length and midpoint of the line segment joining the points of -6 1 and 6 6?
Length = 13 units Midpoint = (0, 3.5)
What is the perpendicular bisector equation to the line segment of -1 -6 and 5 -8?
Points: (-1, -6) and (5, -8) Midpoint: (2, -7) Perpendicular slope: 3 Perpendicular bisector equation: y = 3x -13
Distance between 8 -13 and 1 -7 Midpoint between 8 -13 and 1 -7?
For the distance, use the Pythagorean formula. For the midpoint, take the average of the x-coordinates, and the average of the y-coordinates.
