-4.5
Endpoints: (-8, 12) and (-13, -2) Midpoint: (-10.5, 5)
Midpoint: (-10.5, 5)
The midpoint is the point (-10.5, 5) .
To find the midpoint of the segment with endpoints H(8, 13) and K(10, 9), use the midpoint formula: ( M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) ). Plugging in the coordinates, we get ( M = \left( \frac{8 + 10}{2}, \frac{13 + 9}{2} \right) = \left( \frac{18}{2}, \frac{22}{2} \right) = (9, 11) ). Therefore, the coordinates of the midpoint are (9, 11).
Endpoints: (-1, -6) and (5, -8) Midpoint: (2, -7) Slope: -1/3 Perpendicular slope: 3 Perpendicular bisector equation: y - -7 = 3(x -2) => y = 3x -13
End-points are (-13, 19) and (4, -7). The midpoint of the segment is (-4.5, 6). The X-coordinate is-4.5 we discuss about it.
Endpoints: (-8, 12) and (-13, -2) Midpoint: (-10.5, 5)
Midpoint: (-10.5, 5)
The midpoint is the point (-10.5, 5) .
Points: (-4, -14) and (-22, 9) Midpoint: (-4-22)/2, (-14+9)/2 => (-13, -2.5)
What is the location of the point on the number line that is 1/4 of the way from A=37 to B=13
It is the distance between its endpoints of v and s
Endpoints: (-1, -6) and (5, -8) Midpoint: (2, -7) Slope: -1/3 Perpendicular slope: 3 Perpendicular bisector equation: y - -7 = 3(x -2) => y = 3x -13
It is [(3 + -13)/2, (3 + -13)/2] = [-10/2, -10/2] = (-5, -5)
Length = 13 units Midpoint = (0, 3.5)
Points: (-1, -6) and (5, -8) Midpoint: (2, -7) Perpendicular slope: 3 Perpendicular bisector equation: y = 3x -13
For the distance, use the Pythagorean formula. For the midpoint, take the average of the x-coordinates, and the average of the y-coordinates.