FORMULA: (n [squared] -- 3n) / 2 (18 [squared] -- 3 x 18) / 2 = (324 -- 54) / 2 = 270 / 2 = 135 Easy as Pi ;)
Using the diagonal formula: 0.5*(182-54) = 135 diagonals
252 diagonals
There are 275 diagonals in a 25 sided polygon
0.5*(152-45) = 90 diagonals
many triangles does a regular 46-gon have
To find the number of diagonals in an 18-gon, you can use the formula ( D = \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For an 18-gon, this gives ( D = \frac{18(18-3)}{2} = \frac{18 \times 15}{2} = 135 ). Therefore, an 18-gon has 135 diagonals.
Using the diagonal formula: 0.5*(182-54) = 135 diagonals
It has 54 diagonals
It has 495 diagonals.
252 diagonals
There are 119 diagonals.
78
170
0.5*(152-45) = 90 diagonals
39*36/2 = 702 diagonals.
There are 44 diagonals in an 11 sided undecagon
There are 275 diagonals in a 25 sided polygon