An n sided polygon has n*(n-3)/2 diagonals.
6 * * * * * No! The number of diagonals in a polygon with n sides is 1/2*n*(n - 3). So when n = 7 this gives the number of diagonals in a heptagon is 14.
A polygon with n vertices has n*(n-3)/2 diagonals. So an octagon has 8*5/2 = 20 diagonals. Of those 20 diagonals, 8 are the principal diagonals, the ones joining a pair of opposite vertices
n(n-3)/2
A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
An n sided polygon has n*(n-3)/2 diagonals.
In a polygon with n sides there are n*(n-3)/2 diagonals. For a hexagon, n = 6 giving 9 diagonals in all.
A polygon with n sides has 1/2*n*(n - 3) diagonals. So, for a polygon, with n = 12, there are 54 diagonals.
20 diagonals in Octagan. For n-sided polygon, no of diagonals = (n choose 2 ) - n = 8C2 - 8 = 28 - 8 = 20
A polygon with n sides has n*(n - 3)/2 diagonals. So n = 23 gives 23*20/10 = 230 diagonals
6 * * * * * No! The number of diagonals in a polygon with n sides is 1/2*n*(n - 3). So when n = 7 this gives the number of diagonals in a heptagon is 14.
A polygon with n vertices has n*(n-3)/2 diagonals. So an octagon has 8*5/2 = 20 diagonals. Of those 20 diagonals, 8 are the principal diagonals, the ones joining a pair of opposite vertices
A polygon with n sides has n(n-3)/2 diagonals. A heptagon has 7 sides giving it 7(7-3)/2 = 14 diagonals.
1/2*(n2-3n) = number of diagonals where n is the number of sides of the polygon.
n(n-3)/2
n(n-3)/2
100 sided polygon has = n(n-3)/2 diagonals = 100(100-3)/2 = 4850 diagonals