Draw a picture of this you will see that you can form a triangle with the radius of the circle being 1. This is the hypotenus of the triangle Using trig, x = cos 50 y = sin 50 P is (x,y) = P is (cos 50,sin 50) = (0.643, 0.766)
If you draw this angle in a coordinate system, a right triangle is formed in the second quadrant, with length legs 12 and 5 units. If you label with O the angle that is formed by the terminal side and y-axis, you have tan O = 12/5 and O = tan-1 12/5 = 67.38 degrees Thus, the given angle has a measure of 157.38 degrees (90 + 67.38).
Quadrantal angle
55 degree
a ray of an angle that rotates around the vertex
The difference is the length of the vector.
If you draw this angle in a coordinate system, a right triangle is formed in the second quadrant, with length legs 12 and 5 units. If you label with O the angle that is formed by the terminal side and y-axis, you have tan O = 12/5 and O = tan-1 12/5 = 67.38 degrees Thus, the given angle has a measure of 157.38 degrees (90 + 67.38).
Coterminal Angles are two angles in standard position with the same terminal side.
Quadrantal angle
A standard switch opens the circuit when in the off position, so the answer to your question is no. That said there is a way that it can be done by changing the switch to a single pole double throw switch. The "hot" will come into the switch on the common terminal. The old circuit connects to the top switch handle up terminal. The new circuit connects to the terminal in the handle down position. This setup will leave one of the circuits on all of the time. To over come this situation the switches can be installed in a double gang box. A standard on off switch will control the power to the "hot " that comes into the SPDT switch.
In pea plants, flowers that bud on the top of the plant (terminal position) is dominant, and flowers that bud on the sides of the plants (axial position) is recessive. Cross a heterozygous terminal flowering plant with a homozygous terminal flowering plant
Third quadrant. From the origin (0,0) and on the positive x-axis. Move an arrow/line clockwise from this axis by 135 degrees. The first 90 degrees are in the bottom right (4th)quandrant. The next 90 degrees(to 180 degrees ; includes 135) will be in the bottom left (3rd) quadrant. NB From the positive x-axis ,moving anti-clockwise about the origin the angles are positive. When moving clockwise from the same axis the angles are negative.
Tangent and cotangent positive; other 4 negative.
On a single pole single throw there is no common terminal. On a single pole double throw it is the terminal that is common to both the top and bottom terminals. The "hot" wire is connected to the common terminal so that when the switch is in the up position that terminal becomes energized and there will be no no voltage on the bottom terminal. When the switch is in the down position the bottom terminal becomes energized and there will be no voltage on the top terminal. In relays thisis known as a C form configuration.
What are polar coordinates of (√2, 1)? Solution: Here we need to convert from rectangular coordinates to polar coordinates: P = (x, y) = (r, θ) r = ± √(x^2 + y^2); tan θ = y/x or θ = arc tan (y/x) So we have: P = (√2, 1) r = ± √[(√2)^2 + 1^2] = ± √3 θ = arc tan (y/x) = arc tan (1/√2) = arc tan (√2/2) ≈ 35.3°, which is one possible value of the angle. (√2, 1) is in the Quadrant I. If θ = 35.3°, then the point is in the terminal ray, and so r = √3. Therefore polar coordinates are (√3, 35.3°). Another possible pair of polar coordinates of the same point is (-√3, 215.3°) (180° + 35.3° = 215.3°). Edit: Note the negative in the r value.
Example: Express sin 120⁰ as a function of an acute angle (an angle between 0⁰ and 90⁰).Solution:Each angle θ whose terminal side lies in quadrant II, III, or IV has associated with it an angle called the reference angle, alpha (alpha is formed by the x-axis and the terminal side).Since 120⁰ lies on the second quadrant, then alpha = 180⁰ - 120⁰ = 60⁰.Since sine is positive in the second quadrant, sin 120⁰ = sin 60⁰.Example: Express tan 320⁰ as a function of an acute angle.Solution:Since 320⁰ lies on the fourth quadrant, then alpha = 360⁰ - 320⁰ = 40⁰.Since tangent is negative in the fourth quadrant, tan 320⁰ = -tan 40⁰.
The current terminal or console.
22/45 of 360 degrees = 22/45 x 360 = 7920/45 = 176 degrees