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Q: Can 3 congruent regular hexagons be drawn to create 10 distinctive area?
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Related questions

Is it possible to create a tessellation using only regular hexagons?

Yes


Is it possible to create a regular tesselation with a regular polygon?

Certain polygons, yes. Squares, Triangles and Hexagons are all shapes which, in their regular form, can tessellate. Other polygons cannot.


What shape can be used to create a regular tessellation?

All triangles will tessellate. All quadrilaterals will tessellate There are 15 classes of convex pentagons (the latest discovered in 2015) which will tessellate. Regular hexagons will tessellate. In addition, there are 3 classes of irregular convex hexagons which will tessellate. No convex polygon with 7 or more sides will tessellate.


how many rhombuses would create 5 hexagons?

9


What shapes create a pure tessellation?

Whatshapes/pictures can create tessellations?Triangles,hexagons & squares.


If I have two hexagons how many rectangkes do I need to create a hexagonal prism?

Six of them.


What type of polygon is needed to make a tessellation?

All triangles will tessellate. All quadrilaterals will tessellate There are 15 classes of convex pentagons (the latest discovered in 2015) which will tessellate. Regular hexagons will tessellate. In addition, there are 3 classes of irregular convex hexagons which will tessellate. No convex polygon with 7 or more sides will tessellate.


Three congruent regular hexagons can be drawn in such a way that all of them overlap each other and create exactly ten distinct areas or compartments?

First, a hexagon has 6 sides. Second, congruent means the polygons are the same size and shape. Third, regular hexagon means that all of the angles and the same and the lengths of the sides are the same. For my explanation, let's work with squares. If you were to overlap two perfect squares, you would get at 1 area. Rotate one of those squares, and you will get 8 areas, 4 on the inside and 4 on the outside. Since there is also a center area, we have 9 areas. Working with two hexagons would give you 1 or 13 areas. Obviously, adding a third square or hexagon will not achieve 10 areas, so you can stop here. ------ If you overlap 3 hexagons you get 3 sections that are unique to each hexagon 1 section in the middle that is part of each hexagon 3 sections that are shared between only 2 hexagons Those 7 are straightforward - I drew 3 hexagons in powerpoint to visualize it The last 3 are a matter of interpretation, but they are there. it depends on what is meant by "distinct." There are an additional 3 sections that are made up of the outlines of the 3 sections that shared between only two hexagons plus the section in the middle. That gets you to 10. My 2 cents is that this is a poorly worded question because the answer could be 7 or 10 depending on the interpretation of distinct.


Can a segment bisector create two congruent segments?

By definition, a segment bisector always created two congruent segments.


Which transformations create congruent figures?

Translation, rotation, reflection


What has angles and is not congruent to another shape?

There can be no such object since it is always possible to create an identical shape and then the two shapes would be congruent.


Does a diagonal of a square always create 2 congruent triangles?

Yes