be equidistant from the center of the circle.
APEX!
They must be congruent.
congruent
The triangles must be congruent.
Yes, any diameter which is perpendicular to a chord bisects said chord. This can be proved most easily with a picture, but is proved using a congruent triangle proof. Both triangles include the points at the center of the circle and the intersection of the diameter and chord. The other points should be the endpoints of the chord. They are congruent by hypotenuse leg; it was given that they are right triangle by the "perpendicular", the "leg" is the segment between the center of the circle and the intersection, and it is equal in both triangles because it is the same segment in both triangles. The hypotenuses are equal because both are radii of the circle. Because the triangles are congruent, their sides must be so the two halves of the chord are congruent, and therefore the chord is bisected by the diameter.
Yes. A circle is defined as the set of all points in a plane equidistant from a given point (the center of the circle) - hence - all points of a circle must be co-planar by definition.
They must be congruent.
congruent
If two chords of a circle bisect each other, they must intersect at a point that is equidistant from both endpoints of each chord. By the properties of circles, the perpendicular bisector of any chord passes through the center of the circle. Since the two chords bisect each other at the same point and are both perpendicular to the line connecting their endpoints, this point must also be the center of the circle, making both chords diameters of the circle. Thus, if two chords bisect each other, they are indeed diameters of the circle.
they must be in the same circle or congruent circles they must have the same central angle measure
Yes, two arcs of a circle are congruent if and only if their associated radii are congruent. This is because congruent arcs subtend equal angles at the center of the circle, which means the radii connecting the center to the endpoints of the arcs must also be equal in length. Thus, the congruence of the arcs directly correlates to the congruence of their respective radii.
all the angles measure up to be the sameTwo segments that are both congruent to a third segment must be congruent to each otherAll of the radii of a circle are congruent
The triangles must be congruent.
Angles that are congruent and supplementary must be right angles.
Yes, any diameter which is perpendicular to a chord bisects said chord. This can be proved most easily with a picture, but is proved using a congruent triangle proof. Both triangles include the points at the center of the circle and the intersection of the diameter and chord. The other points should be the endpoints of the chord. They are congruent by hypotenuse leg; it was given that they are right triangle by the "perpendicular", the "leg" is the segment between the center of the circle and the intersection, and it is equal in both triangles because it is the same segment in both triangles. The hypotenuses are equal because both are radii of the circle. Because the triangles are congruent, their sides must be so the two halves of the chord are congruent, and therefore the chord is bisected by the diameter.
One side cannot be congruent: it must be congruent to something!
The seven sides, in order, must be congruent, as must the seven angles.
Two arcs are congruent if they have the same measure in degrees or radians and are parts of the same circle or circles of equal radius. Additionally, if the arcs are on different circles, they must subtend the same central angle. This ensures that the lengths of the arcs are equal, meeting the congruence condition.