Assuming that the charhe 'q' is uniformly distributed ina sperical volume of radius Discuss the variation of Electric intensity
3,734 feet of fencing.
Your electric company- SMUD, for example.
mine is about 380 a month
electric plugs because of the heat and electricity transmitted into it. Conductivity is really a element to transmit heat energy or electricity.
If the field lines were not perpendicular to the surface, then they could be decomposed into components perpendicular and parallel to the surface. But if there is an E-field along the surface, the surface is no longer an equipotential.
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Tes
If the charge is uniformly distributed over the shell, then the electric field is zero everywhere inside.
gauss law E=Q/(E0*A) Q=793*10^-6 r=1.61 A=4*pi*r^2 E0 = 8.8*10^-12 solve for E
Increase the magnitude of the electric current.
Electric field is dependent on the magnitude of the electric charge, E = qzc/r2
The magnitude of the electric field is 2.5.
If the charge is evenly distributed over the sphere ... as it would be if the sphere is a conducting material ... then the electric field at the center of the sphere is zero. If the sphere is not a conductor and the charge hasn't been applied to it symmetrically, then the magnitude and direction of the electric field at the center depend on every little detail of exactly how it's distributed on the sphere.
The magnitude of the electric field is 2.5.
That depends on the strength of the electric field, and on the length of time the electron has been experiencing it. An electron in an electric field accelerates uniformly.
The magnitude of the electric potential is dependent upon the particle's charge and the electric field strength.
only if there is an earthquake