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Yes and it will have 25 sides

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Q: Could a regular polygon have interior angles of 165.6?
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If the sum of the interior angles of a polygon equals 1080 degree's what is the measure of each interior angle of the polygon?

Sum of interior angles = (n-2)*180 degrees = 1080 deg So (n-2) = 1080/180 = 6 => n = 8. The polygon is, therefore, an octagon. However, there is no reason to assume that the interior angles of this polygon are all the same - they could all be different with the only constraint being their sum. IF, and that is a big if, the polygon were regular, then all its angles would be equal and each interior angle = 1080/8 = 135 degrees.


How many sides does a polygon have with interior angles of 45 degrees?

22/3 sides.-- The smallest possible number of sides for a polygon is 3, in a triangle.If the triangle is regular, then each interior angle is 60 degrees.-- The next polygon is the quadrilateral, with 4 sides. If the quadrilateralis regular, then each interior angle is 90 degrees.-- We can see that as the number of sides increases, the interior angles get bigger.-- So the triangle is the polygon with the smallest interior angles.And those are 60 degrees, so a polygon with all45-degree interior anglesisn't possible. Some of them could be, but never all.


How many sides in a polygon whose interior angle is 174?

It could be three. It could be a triangle with angles of 174, 3 and 3 degrees. If it is a REGULAR polygon, though, there is a more specific answer. Interior angle = 174 deg implies exterior angle = 6 deg. Sum of ext angles = 360 deg so there must be 360/6 = 60 sides to the polygon.


Is A Convex Polygon That Has More Than Four Sides And That Has Congruent Interior Angles Is A Regular Polygon?

Not necessarily.The polygon does not need t have more than 4 sides.All its sides need to be congruent.For example, consider a hexagon with all equal angles. If you could take hold of two opposite vertices and pull them apart you would get al elongated hexagon. All its interior angles would be equal but not the sides. It is, therefore, not regular - for much the same reason that a square is but a rectangle is not.


Is it possible for the sum of the internal angles of a polygon to be 5400 degrees?

# Any exterior angle of a polygon corresponds to an interior angle, and their sum is 180 degrees. # If there are n sides (and therefore n vertices) then the sum of all the interior and exterior angles must be 180n. # The external angles of a polygon total 360 degrees, else it could not be a closed shape. # From the above three points, it follows that the sum of interior angles is given by 180n - 360. So, if there is an integer solution to 180n - 360 = 180(n - 2) = 5400, then the answer to your question is yes. 180(n - 2) = 5400 n - 2 = 30 n = 32 A polygon with 32 sides fulfills the criterion. That would be, hmmm, a triacontakaidigon, of course.

Related questions

Describe how you could find the angle sum of a regular polygon that has N sides?

Interior angles of any polygon: (N-2)*180 = sum of interior angles when N is the number of sides


If the sum of the interior angles of a polygon equals 1080 degree's what is the measure of each interior angle of the polygon?

Sum of interior angles = (n-2)*180 degrees = 1080 deg So (n-2) = 1080/180 = 6 => n = 8. The polygon is, therefore, an octagon. However, there is no reason to assume that the interior angles of this polygon are all the same - they could all be different with the only constraint being their sum. IF, and that is a big if, the polygon were regular, then all its angles would be equal and each interior angle = 1080/8 = 135 degrees.


How many sides does a polygon have with interior angles of 45 degrees?

22/3 sides.-- The smallest possible number of sides for a polygon is 3, in a triangle.If the triangle is regular, then each interior angle is 60 degrees.-- The next polygon is the quadrilateral, with 4 sides. If the quadrilateralis regular, then each interior angle is 90 degrees.-- We can see that as the number of sides increases, the interior angles get bigger.-- So the triangle is the polygon with the smallest interior angles.And those are 60 degrees, so a polygon with all45-degree interior anglesisn't possible. Some of them could be, but never all.


How many sides does a polygon have if the interior angle is 3580?

If an interior angle is 3580o there is a slight problem: a full turn is 360o and 3580o is more than a full turn.If the sum of the interior angles is 3580o, there would benumber_of_sides = 3580o ÷ 180 + 2= 218/9Another slight problem as the number of sides must be an integer.Thus I am lead to assume the question is:How many sides does a regular polygon have if one interior angle is 358o?But an interior angle of a regular polygon can't be greater than 180o. Another problem.ONE interior angle could be 358o, but then there could be three more angles of 1o, 0.5o and 0.5o; or four more angles of 1o, 1o, 1o, 179o; or five more angles, etc.Only solution possible is that there is no such (regular) polygon, or it is a polygon with an indeterminate number of sides (if one interior angle is 358o).


Interior angle of a polygon has a measure of 140?

It could be an obtuse triangle. If it were a regular polygon then each of its external angles would be 180 -140 = 40 degrees. The sum of the external angles of any polygon is 360 degrees. So if each is 40 degrees, there must be 360/40 = 9 of them. So the polygon is a nonagon, BUT ONLY IF IT IS A REGULAR POLYGON.


What is the sum of the measure of the interior angles of a regular polygon if each exterior angle measures 90 degrees?

360 degrees, it could be a square or a rectangle


How many sides in a polygon whose interior angle is 174?

It could be three. It could be a triangle with angles of 174, 3 and 3 degrees. If it is a REGULAR polygon, though, there is a more specific answer. Interior angle = 174 deg implies exterior angle = 6 deg. Sum of ext angles = 360 deg so there must be 360/6 = 60 sides to the polygon.


Is A Convex Polygon That Has More Than Four Sides And That Has Congruent Interior Angles Is A Regular Polygon?

Not necessarily.The polygon does not need t have more than 4 sides.All its sides need to be congruent.For example, consider a hexagon with all equal angles. If you could take hold of two opposite vertices and pull them apart you would get al elongated hexagon. All its interior angles would be equal but not the sides. It is, therefore, not regular - for much the same reason that a square is but a rectangle is not.


How many side does a regular polygon have if the sum of its interior angles is 2700?

The polygon would have 17 sides. Here is why: n = Number of Sides s = Sum of Interior Angles n = (s / 180) + 2 So n = (2700 / 180) + 2 n = 15 + 2 n = 17 Best I could explain it :)


A convex polygon has 17 sides What is the measure of its interior angles?

Without knowing whether it is a regular (all angles equal) polygon, it's impossible to state a specific angle for all vertices. All we know for sure is that the sum of all angles will equal 360o.If it were a regular 17-sided polygon, it wouldn't be necessary to state that it is convex (because all angles would be equal, and thus it would be impossible fro any to be greater than 120o). In that case we could answer the question fully: every interior angle would be 360o/17, or roughly 21.2o.


How many sides does a polygon have if ecach interior angles measure is equal to the exterior angles measure?

It will have 4 sides which could be a square or a rectangle


What is a polygon with all interior sides equal?

A polygon can only have sides. There are no interior or exterior sides: all sides are the boundaries of a polygon. They could be called equilateral although that names seems to be reserved for triangles.