If it's a right angle triangle then its hypotenuse is 10ft and its sides are 6ft and 8ft
Assuming the shape is a triangle, the area is 11.40 sq ft, approx.
I can't understand your question. You need to give some more information. Are the sides of the triangle 6ft and 8ft? What is the angle between these sides, or the length of the third side? And how can I say how many more inches are needed unless I know how much space Mike already has? You will have to rethink this question.
It is not possible to determine the area of a quadrilateral given only the length of its four sides.
It is not posible to give an answer to the question. The shape for which the area is required is unknown. The question gives three measures but they are clearly NOT the sides of a triangle.It is not posible to give an answer to the question. The shape for which the area is required is unknown. The question gives three measures but they are clearly NOT the sides of a triangle.It is not posible to give an answer to the question. The shape for which the area is required is unknown. The question gives three measures but they are clearly NOT the sides of a triangle.It is not posible to give an answer to the question. The shape for which the area is required is unknown. The question gives three measures but they are clearly NOT the sides of a triangle.
If it's a right angle triangle then its hypotenuse is 10ft and its sides are 6ft and 8ft
If the sides of a right angle triangle are 6 feet and 8 feet then by using Pythagoras' theorem the hypotenuse will be 10 feet
Using Pythagoras' theorem the 3rd side is 8 feet providing it is a right angle triangle.
5+2x=17 2x=12 x=6 so the remaing sides are each 6ft
It is a right angle triangle and by using Pythagoras' theorem the length of its hypotenuse is 10 feet.
Area of any triangle: 0.5*base*height
The triangle only has one height, not two. The height is NOT the length of the other two sides, besides the one it's sitting on. The height is exactly that: the height. It's how high the ceiling has to be if you want to stand that triangle up in a room. In general, the height is LESS than the length of either side that the triangle is not sitting on.
It depends on what the shape is! You could have an equilateral traiangle of 2 ft sides. Or an isosceles triangle with sides A and 6 - 2A where 2/3 < A < 3. Scalene triangles are also possible. For a square or rhombus, you could have sides of 1.5ft each. For a rectangle, (or parallelogram) pick ANY number 0 < B < 1.5 and let L = 3 - B Then a rectangle with length L ft and breadth B ft will have a perimeter of 6 ft. Or you could have a quadrilateral all of whose sides are different. Provided they added to 6, you have your perimeter. Similarly, you will have a range of options with pentagons, hexagons, etc.
The area of the rectangle is the product of the length of the sides (provided the units of length are the same). Imagine a rectangle 6ft long and 10ft wide. You could even draw it if it helps. 6 multiplied by 10 is 60, so the area of a 6ft*10ft rectangle is 60ft2 or 60 sq. ft.
24ft (4 sides x 6 = 24)
Assuming the shape is a triangle, the area is 11.40 sq ft, approx.
I can't understand your question. You need to give some more information. Are the sides of the triangle 6ft and 8ft? What is the angle between these sides, or the length of the third side? And how can I say how many more inches are needed unless I know how much space Mike already has? You will have to rethink this question.