It depends on what the shape is!
You could have an equilateral traiangle of 2 ft sides.
Or an isosceles triangle with sides A and 6 - 2A where 2/3 < A < 3.
Scalene triangles are also possible.
For a square or rhombus, you could have sides of 1.5ft each.
For a rectangle, (or parallelogram) pick ANY number 0 < B < 1.5 and let L = 3 - B
Then a rectangle with length L ft and breadth B ft will have a perimeter of 6 ft.
Or you could have a quadrilateral all of whose sides are different. Provided they added to 6, you have your perimeter.
Similarly, you will have a range of options with pentagons, hexagons, etc.
Perimeter = 2*(4ft 10in+6ft 4in) = 22ft 4in
24
area 63 and perimeter is 32
The perimeter will be tripled.
21 x 2 has greatest perimeter
A rectangle has two dimensions - length and width. Only if both dimensions are doubled, then the perimeter will be doubled.
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
5ft+5ft+6ft+6ft+8ft=30ft
The answer depends entirely on how the dimensions change. It is possible to change the dimensions without changing the perimeter. It is also possible to change the dimensions without changing the area. (And it is possible to change the area without changing the perimeter.)
24ft (4 sides x 6 = 24)
834.84 feet
To know the perimeter, you must know the dimensions (length and width). But there are many possible dimensions if you have 24 square feet.