Yes.
to add to that
a vertex must be connected to at least 3 edges to be 3d, an edge is always connected to 2 vertexes, so the closest the two can ever be is
vetexes x 3 = edges x 2,
but when working with any platonic solid you can follow this:
vertexes x (faces / vertexes) x [edges on one side] = edges x 2
or
vertexes x [faces meeting at one vertex] = edges x 2
when working with any other polyhedron
[vertexes with x amount of faces] x (x) + [vertexes with y amount of faces] x (y) ...{and so on} = edges x 2
A shape with more than 12 edges is a dodecahedron which has 30 edges
A heptagonal prism has 14 vertecies and 21 edges.
I don't know but I need to know =p
The shape would be impossible. The faces and vertices have to add up to two more than the edges.
Yes, an example of this is a sphere which does not have any edges. If you had intended to ask if there are any polyhedra with less than three edges, the answer to that would be no, as the only figure constructable from three distinct lines is a triangle.
an octagon
Every triangle has three vertices (vertexes).If it has less than 3 or more than 3, it isn't a triangle.
check a reference book
The plural form of vertex is verteces or vertexes.
Vertexes or Vertices. (VERT-uh-seize)
3 more
A shape with more than 12 edges is a dodecahedron which has 30 edges
A cube has 12 edges whereas a cylinder has 2 edges so therefore it has 10 more edges than a cylinder.
you take face, than add the vertice, and subtract 2 from it this works for almost al polyhedrons but it doesn't work for a cylinder
9 edges n 5 faces, 4 more edges
yes it does has more than 3 pairs of parrallel edges
12 * * * * * NO! It has 4 more edges.