Best Answer

Yes.

to add to that

a vertex must be connected to at least 3 edges to be 3d, an edge is always connected to 2 vertexes, so the closest the two can ever be is

vetexes x 3 = edges x 2,

but when working with any platonic solid you can follow this:

vertexes x (faces / vertexes) x [edges on one side] = edges x 2

or

vertexes x [faces meeting at one vertex] = edges x 2

when working with any other polyhedron

[vertexes with x amount of faces] x (x) + [vertexes with y amount of faces] x (y) ...{and so on} = edges x 2

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Q: Do all polyhedrons have more edges than vertexes?

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A shape with more than 12 edges is a dodecahedron which has 30 edges

A heptagonal prism has 14 vertecies and 21 edges.

I don't know but I need to know =p

The shape would be impossible. The faces and vertices have to add up to two more than the edges.

Yes, an example of this is a sphere which does not have any edges. If you had intended to ask if there are any polyhedra with less than three edges, the answer to that would be no, as the only figure constructable from three distinct lines is a triangle.

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