Any polyhedron other than a pyramid.
A cube has 8 vertices and 6 faces. Therefore a cube has 2 more vertices than faces.
Bipyramids are a class of polyhedra with more faces than vertices.
A cube is a geometric shape which has 6 faces and 8 vertices ie .2 more vertices than faces
A cube has eight vertices and six faces (think of a die!).
Any polyhedron other than a pyramid.
A cube has 8 vertices and 6 faces. Therefore a cube has 2 more vertices than faces.
Bipyramids are a class of polyhedra with more faces than vertices.
A cube is a geometric shape which has 6 faces and 8 vertices ie .2 more vertices than faces
No. A cube has 6 faces and 8 vertices - it has exactly 2 more vertices than faces.
A cube has eight vertices and six faces (think of a die!).
the answer is cylinder
Shapes that have more than six faces include polyhedrons such as the cube, which has six square faces, and the octahedron, which has eight triangular faces. Additionally, shapes like the dodecahedron have twelve pentagonal faces, and the icosahedron has twenty triangular faces. These shapes are examples of polyhedrons with more than six faces.
Rectangular Prism
The shape would be impossible. The faces and vertices have to add up to two more than the edges.
Tetrahedron- (4 faces, 4 vertices) Octahedron- (8 faces, 6 vertices) Cube- (6 faces, 8 vertices)
you take face, than add the vertice, and subtract 2 from it this works for almost al polyhedrons but it doesn't work for a cylinder