Inverse variation does not pass through the origin, however direct variation always passes through the origin.
Assuming both the scales on the graph are linear (that is to say that the numbers go up evenly) then YES, a graph which shows direct proportion must be a straight line. It must also pass through the origin (0,0). A straight line which does not pass through the origin is NOT showing direct proportion. Duncan
For any polynomial equation, there must be no constant term.For equations in general there is no easy way. Substitute 0 for each of the variables and if the resulting expression is 0 then the line passes through the origin.
13 good luck
Slope = 1Y-intercept = 0Y = X
All direct variation graphs are linear and they all go through the origin.
Not always
No.
it is just that- a linear function that goes through ther origin. ======================================================= Any equation y = ax, where a is a constant, will do so.
The graphs of those two equations are straight lines, each of which passes through the origin. The origin is the common solution ... the point (0, 0).
If two quantities are proportional, then they have a constant ratio.If the ratio is not constant, the two quantities are said to be non-proportional.Proportional will always go through the origin on a graph. (0,0)Graph will always be a straight line.Non-proportional line does not go through the origin.
Either a straight line through the origin or a hyperbola.
The formula direct variation is xk=y, where k is the constant of variation.Direct variation functions always pass through the origin. Direct variation functions are linear functions (goes in a straight line), except that they pass through the origin. Regular linear functions don't pass through the origin. That is the only difference.
They are straight lines through the origin and their gradient is the constant of proportionality.
the line that crosses through the origin
A straight line that goes through the origin.
No, the particle's angular momentum depends on both its linear momentum and its distance from the origin. If the particle is moving along a line passing through the origin, its angular momentum will not necessarily be zero unless its linear momentum is also zero.