Perimeter = 2 lengths + 2 widths
1/2 perimeter = length + width
Length = 1/2 perimeter - width
Area = length x width
That's (1/2 perimeter - width) x (width) .
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
perimeter, area =35.0,66.0 , Travis Garner Rocks!
Perimeter = 24 inches Area = 35 square inches
area is length times width
you need length and width length multiply width = area length + length + width + width = perimeter
perimeter is the measure around the figure; area is the measure within the figure formula: perimeter: length+length+width+width=perimeter (for square or rectangle) area: length times width= area ( for square or rectangle)
18cm is the area and perimeter. the width is 3cm.
If you are given the width and the perimeter, then figure out what the length is then calculate the area... hope this helps :)
Area = Length*Width so Width = Area/Length. Therefore the Width can be calculated. Then, perimeter = 2*(Length + Width) and everything on the right hand side of the equation is known so the perimeter can be calculated.
The perimeter is equal to length + length + width + width while area is length x width. Both measurements are found by using width and length.
Perimeter: Add the length of the four sides. Area: Multiply length x width.
Area = Legth x Width In a square, Length = Width Therefore Area = Length x Length (or Width x Width) Area = Length squared Length = Square Root of 800 Perimeter = 4 x length Perimeter = 4 x Square Root of 800 Perimeter = 113.14
Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.
The area is the length times the width. The perimeter is two times the length plus two times the width.
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.
Perimeter minus two times the width will give you the two times the length. Area is found by multiplying the length by the width.