If 1 or 2 of the obtuse angles are 'bent into' the hexagon then you can do it.A hexagon has 720° sum of interior angles. If you have 2 right angles, then that's 180°, leaving 540° to be distributed over four angles. If the two acute angles are 89°, then that leaves 362° to be divided between two angles, so at least one of these two angles will need to be greater than 180°. Below is my text graphics attempt of one possibility (ignore the 'dot'). Note that both of the obtuse angles are greater than 180°:|\_/||__.|Look at the related link to play with different angle possibilities for polygons.
You are describing a hexagon, a closed shape with six sides. A hexagon has six angles, but since two of them are less than a right angle (90 degrees), the other four angles must be greater than a right angle. This means that a hexagon does not have any right angles.
iscoceles
1 vertex less than a hexagon is a pentagon. 2 angles more than a triangle is a pentagon.
all angles that are more then 180 degrees. * * * * * No, angles which arer more than 180 degrees are called reflex angles. An obtuse angle is one whose measure is between 90 and 180 degrees. It is, therefore, always smaller than 180 degrees.
Yes they are (at least, in a regular hexagon).
You are an irregular hexagon.
If it is a regular hexagon then each of its 6 interior angles are 120 degrees
More- each angle is over 90 degrees.
None. Though there can be ten if the hexagons are concave hexagons.
Acute angles
0 angles
An angle smaller than a right angle - is an acute angle. Larger than a right angle, but smaller than 180 degrees is an obtuse angle. Angles between 180 and 360 degrees are reflex angles.
there are 4 angles and normally, there would be 2 angles that are smaller than a right angle Except of cause if the parallelogram is a square or a rectangle, all angles are equal to 90 i.e. right angle
If 1 or 2 of the obtuse angles are 'bent into' the hexagon then you can do it.A hexagon has 720° sum of interior angles. If you have 2 right angles, then that's 180°, leaving 540° to be distributed over four angles. If the two acute angles are 89°, then that leaves 362° to be divided between two angles, so at least one of these two angles will need to be greater than 180°. Below is my text graphics attempt of one possibility (ignore the 'dot'). Note that both of the obtuse angles are greater than 180°:|\_/||__.|Look at the related link to play with different angle possibilities for polygons.
You are describing a hexagon, a closed shape with six sides. A hexagon has six angles, but since two of them are less than a right angle (90 degrees), the other four angles must be greater than a right angle. This means that a hexagon does not have any right angles.
As far as I know, a hexagon has 6 angles whether it is regular or not. Some may be obtuse angles, but they still count. So a hexagon where some of the sides go 'in' rather than 'out' is still a hexagon.