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Ef is a median of trapezoid ABCD the length of AB is 12 and the length of CD is 18 the length of BF is 4 what is the length of FC?
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Ef is a median of trapezoid abcd the length of ab is 12 and the length of CD is 18?
15 units
EF is a median of trapezoid ABCD the length of ab is 12 and the length of CD is 18 what is the length of ef?
15 units
Ef is a median of isosceles trapezoid abcd the length of ab is 12 and the length of CD is 18 the length of bf is 5 what is the length of de?
it is 5. :)
What is the length of DE where EF is a median of trapezoid ABCD the length of AB is 12 and the length of CD is 18?
The median of a trapezoid is one half of the sum of the two sides. So EF is 1/2 (12+18) = 1/2 (30) = 15.
Ef is a median of isosceles trapezoid abcd the length of ab is 12 and the length of CD is 18 the length of bf is 5 what is the length of ad?
15 units
Ef is a median of trapezoid abcd the length of ab is 12 and the length of CD is 18?
15 units
EF is a median of trapezoid ABCD the length of ab is 12 and the length of CD is 18 what is the length of ef?
15 units
Ef is a median of isosceles trapezoid abcd the length of ab is 12 and the length of CD is 18 the length of bf is 5 what is the length of de?
it is 5. :)
What is the length of DE where EF is a median of trapezoid ABCD the length of AB is 12 and the length of CD is 18?
The median of a trapezoid is one half of the sum of the two sides. So EF is 1/2 (12+18) = 1/2 (30) = 15.
Ef is a median of isosceles trapezoid abcd the length of ab is 12 and the length of CD is 18 the length of bf is 5 what is the length of ad?
15 units
EF is a median of isosceles trapezoid ABCD. AB is equal to 12 EF?
The answer will depend on which two sides are bisected by E and F.
If EF is a median of isoceles trapeziod ABCD. The length of AB is 12 and the length of CD is 18. the length of BF is 5. What is the length of DE?
The length of DE is 5.
Given ABCD what is the length of AB?
12
Isosceles trapezoid abcd has an area of 276 in squared if ad equals 13 inches and de equals 12 inches find ab?
Isosceles trapezoid ABCD has an area of 276 If AD = 13 inches and DE = 12 inches, find AB.
What is the area of an isosceles trapezoid whose median has a length of 12 whose legs each have a length of 9 and whose altitude has a length of 8?
well since we know that the area of a isosceles tapezoid is the height(altitude)times twice the median divided by two, so the answer is 9(2)(12)/2=108
The bases of the trapizoid are 12 and 16 Find the length of the median?
To find the median of a trapezoid, you add the bases together then divide by 2. So in this case the equation would be: (12 + 16) ÷ 2 =M. 28 ÷ 2= M M= 14
ABCD is a rectangle and AE equals 12 what is the length of DB?
24;
