area of a circle = pi*r2
Area= Pi r squared
The equation for area of a circle is A=pi x R x R. A semicircle is half a circle, so we calculate the area of a circle and divide by 2. The area of the circle would be approximately 1384.74. Thus the area of the semicircle would be 692.37.
Area of a circle = pi*radius squared Circumference of a circle = 2*pi*radius or diameter*pi
Solve the equation for the area of the circle (area = pi x radius2) for radius. Multiply the radius by 2 to obtain the diameter.
The equation for the area A of a circle is A = pi*r2, where r is the radius of the circle. If you plug in 7850 for the area, you get pi*r2 = 7850. Assuming pi = 3.14, the equation then simplifies to r2 = 7850/3.14 = 2500. Taking the square root of both sides gives you the radius r as 50.
Area of a circle = (pi) (R2)R = radius of the circle = 1/2 of its diameter
π×(radius)2http:/www.mathwarehouse.com/geometry/circle/area-of-circle.php
Area of a circle is defined by the equation: A = pi * r2. pi = 3.14159 & r = 28. Substitute into the equation: A = 3.14159 * 282. Area = 2463 cm2.
Area of a circle = 3.14 * r2 Thus, radius, r = root of ( Area of a circle / 3.14 ) --------- equation 1 Circumference of circle = 2 * 3.14 * r Therefore, from (equation 1), Circumference = 2 * 3.14 * root of ( Area of a circle / 3.14 ). In a nutshell, first find the radius and then the circumference.
The area of the base of a cylinder is the same as the area of a circle. The equation for the area of a circle is: Pi r squared
2x3.14r
Area= Pi r squared
If you are referring to a circle, divide the diameter by 2 (to get the radius), then use the standard equation for the area of a circle. For your reference, this is the equation: area = pi x radius2
Area of the circle in square inches = pi*82
Area of a circle = pi*radius squared Circumference of a circle = 2*pi*radius or diameter*pi
The area of a circle is given by: pi multiplied by the square of the radius. So if the radius is 15, the area is 225pi (225 is 15 squared)
Rewrite the above program so that the program accepts any value for the radius then recalculate the area of the circle.