Solve the equation for ' y '.
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.
It is (x + 2)^2 + (y + 3)^2 = 9
The equation is (x - h)2 + (y - v)2 = r2
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
There are different standard forms for different things. There is a standard form for scientific notation. There is a standard form for the equation of a line, circle, ellipse, hyperbola and so on.
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The Pythagorean theorem is used to develop the equation of the circle. This is because a triangle can be drawn with the radius and any other adjacent line in the circle.
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
32+62=45 so the standard form is x2+y2=45
well you would times that by: R2=D*3.14(pie)=C
A standard form of a linear equation would be: ax + by = c
The radius of the circle decreases when you make the circle smaller.
There is no such thing as a standard equation. Furthermore, there are standard forms - all different - for the equation of a line, a circle, a plane, a parabola, an ellipse and so on. the question needs to be more specific.
You should increase the radius in the standard equation of a circle centered at the origin. The general form is ( x^2 + y^2 = r^2 ), where ( r ) is the radius. By increasing ( r ), you extend the distance from the center to any point on the circle, making it larger.
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