Area of a circle = pi*radius squared
Circumference of a circle = 2*pi*radius or diameter*pi
Solve the equation for ' y '.
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.
It is (x + 2)^2 + (y + 3)^2 = 9
The equation is (x - h)2 + (y - v)2 = r2
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
There are different standard forms for different things. There is a standard form for scientific notation. There is a standard form for the equation of a line, circle, ellipse, hyperbola and so on.
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
9
The Pythagorean theorem is used to develop the equation of the circle. This is because a triangle can be drawn with the radius and any other adjacent line in the circle.
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
32+62=45 so the standard form is x2+y2=45
well you would times that by: R2=D*3.14(pie)=C
A standard form of a linear equation would be: ax + by = c
The given equation appears to have a typographical error as it does not represent a standard circle equation. The standard form of a circle's equation is ((x-h)^2 + (y-k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. If you can provide the correct equation, I can help you determine the circumference, which is calculated using the formula (C = 2\pi r).
The radius of the circle decreases when you make the circle smaller.
The equation provided appears to have a typographical error, as it should likely be in the form of a standard circle equation. If you meant (x^2 + y^2 = 16), the center of the circle is at the coordinates (0, 0). If this is not the correct interpretation, please clarify the equation for an accurate response.