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Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius a in C Programming

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Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius 4 inches?

Approximately 5.66x5.66 in. Or root32 x root32


Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius a?

The largest rectangle would be a square. If the circle has radius a, the diameter is 2a. This diameter would also be the diameter of a square of side length b. Using the Pythagorean theorem, b2 + b2 = (2a)2. 2b2 = 4a2 b2 = 2a2 b = √(2a2) or a√2 = the length of the sides of the square The area of a square of side length b is therefore (√(2a2))2 = 2a2 which is the largest area for a rectangle inscribed in a circle of radius a.


What is the area of the rectangle of largest area that can be inscribed in a circle of radius r?

It is 2*r^2.


What is the area of the largest circle that will fit into a rectangle with dimensions 8.5 cm by 10.6 cm?

56.7 cm2


Find the dimensions of the rectangle with an area of 100 square units and whole-number side lengths that has the largest perimeter or the smallest perimeter?

Type your answer here... give the dimensions of the rectangle with an are of 100 square units and whole number side lengths that has the largest perimeter and the smallest perimeter


What is the side length of the largest possible square that will completely tile a rectangle with the dimensions of 12 cm by 30 cm?

6 cm


What is the area of largest rectangle that can be inscribed between y equals 12-x2 and y equals -2?

It is 56/9*sqrt(42) which is approx 40.32 square units.


Give the dimensions of the rectangle with an area of 100 square units and whole-number side lengths that has the largest perimeter?

w 20; l 30


Find the area of the largest rectangle that can be inscribed in the ellipse below x2a2 plus y2b2 equals 1?

2ab = area The sides of this rectangle are, a * sqrt(2) and b * sqrt(2) The equation of the ellipse reduces to, 0.5 + 0.5 = 1 Greetings, Dim Leed


For a rectangle with a perimeter 72 to have the largest area what dimensions should it have Enter the smaller value first?

Since the largest area would be obtained by having adjacent sides equal to each other, and since a square is at least technically an equilateral rectangle, divide the perimeter of 72 by 4 to get sides of 18 and an area of 324.


If farmer Dan has 100 feet of fencing write an inequality to find the dimensions of the rectangle with the largest perimeter that can be created using 100 feet of fencing?

To find the dimensions of a rectangle with the largest perimeter using 100 feet of fencing, we can express the perimeter ( P ) of a rectangle in terms of its length ( l ) and width ( w ) as ( P = 2l + 2w ). Since the total amount of fencing is 100 feet, we set up the inequality ( 2l + 2w \leq 100 ). Simplifying this gives ( l + w \leq 50 ). The dimensions that maximize the area (which is a related concept) would be when ( l = w = 25 ) feet, creating a square shape.


How big is the largest football pitch?

Camp Nou (Barcelona F.C) see its dimensions at wikipedia (it's the largest legal dimensions)