w 20; l 30
To find the dimensions of a rectangle with the largest perimeter using 100 feet of fencing, we can express the perimeter ( P ) of a rectangle in terms of its length ( l ) and width ( w ) as ( P = 2l + 2w ). Since the total amount of fencing is 100 feet, we set up the inequality ( 2l + 2w \leq 100 ). Simplifying this gives ( l + w \leq 50 ). The dimensions that maximize the area (which is a related concept) would be when ( l = w = 25 ) feet, creating a square shape.
A 4 by 4 and a 1 by 7.
For any given area, the rectangle closest to a square will have the smallest perimeter; and the one that is most "stretched out" has the largest perimeter. In this case, that would be a width of 1 and a length of 2014.
To find the dimensions of the largest rectangular pen that can be enclosed with 64 meters of fence, we can use the formula for the perimeter of a rectangle, which is (P = 2(l + w)), where (l) is length and (w) is width. Setting the perimeter equal to 64 meters gives us (l + w = 32). To maximize the area (A = l \times w), we can express (w) as (w = 32 - l) and find the maximum area occurs when (l = w = 16). Therefore, the dimensions of the largest rectangular pen are 16 meters by 16 meters, making it a square.
That two different shapes may well have the same perimeter, but different areas. As an example, a 3 x 1 rectangle and a 2 x 2 rectangle have the same perimeter, but the area is different.
Type your answer here... give the dimensions of the rectangle with an are of 100 square units and whole number side lengths that has the largest perimeter and the smallest perimeter
The smallest is just over 40 units. At 40 units it is no longer a rectangle but a square. There is no largest perimeter.
Since the largest area would be obtained by having adjacent sides equal to each other, and since a square is at least technically an equilateral rectangle, divide the perimeter of 72 by 4 to get sides of 18 and an area of 324.
The smallest perimeter is 4*sqrt(24) = approx 19.6 cm There is no largest perimeter.
Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius a in C programming
To find the dimensions of a rectangle with the largest perimeter using 100 feet of fencing, we can express the perimeter ( P ) of a rectangle in terms of its length ( l ) and width ( w ) as ( P = 2l + 2w ). Since the total amount of fencing is 100 feet, we set up the inequality ( 2l + 2w \leq 100 ). Simplifying this gives ( l + w \leq 50 ). The dimensions that maximize the area (which is a related concept) would be when ( l = w = 25 ) feet, creating a square shape.
Largest = 86, Smallest 26
Not at all. For example:A square of 2 x 2 will have a perimeter of 8, and an area of 4. A rectangle of 3 x 1 will also have a perimeter of 8, and an area of 3.A "rectangle" of 4 x 0 will also have a perimeter of 8, but the area has shrunk down to zero. The circle has the largest area for a given perimeter/circumference.
A 4 by 4 and a 1 by 7.
If the shapes are similar, such are all circles or all squares, those with the largest perimeters would also have the largest areas. However, in general there is no direct relation. For example a 2 by 2 rectangle has an area of 4 and a perimeter of 8, but a 2000 by 0.0005 rectangle has an area of 1 and a perimeter of 4000.001.
The answer depends on what your criterion for deciding what is "largest". Any rectangle will have an area of 47916 square feet. Its perimeter can be infinitely large.
For any given area, the rectangle closest to a square will have the smallest perimeter; and the one that is most "stretched out" has the largest perimeter. In this case, that would be a width of 1 and a length of 2014.