360/7 = 51.43 degrees (approx).
51 degrees
Each interior angle is approximately 128.57 * * * * * That is only true of a REGULAR heptagon. The question does not state that it is regular.
The 7 exterior angles of a septagon or a heptagon add up to 360 degrees
Each exterior angle will measure 9 degrees
Providing that it is a regular hexagon then each exterior angle will measure 60 degrees
51.428571° is the measure of an exterior angle of a heptagon. You can always find the measurements of a regular polygon by dividing 360 by the amount of sides.
51 degrees
An exterior angle is 360/7 = 51.4286 degrees. So interior angle is 180 - exterior angle = 128.57 degrees (approx).
It is the regular triangle whose exterior angles are greater than the regular heptagon
There is no such thing as a hectogon. A heptagon has 7 vertices. Each exterior angle of a regular heptagon is 360/7 degrees. So each interior angle is 180 - 360/7 = 128.57 degrees (approx).
The exterior angle of a n-gon is 360/n degrees. So for a heptagon, the exterior angle is 360/7 = 51.429 degrees.
It is the regular equilateral triangle whose each exterior angle is 120 degrees
It is the equilateral triangle that has the largest exterior angle of 120 degrees
That depends on the type of triangle it is but if it's an equilateral triangle then its exterior angle is greater than that of a regular heptagon
Each angle is about 51.43 degreesheptagon=7 sides, 7 anglesexterior angles sum=360360/7= about 51.4285
The largest exterior angle measure is 120o. It is the exterior measure of an equilateral triangle (which is a regular polygon).
The exterior angle of a regular n-sided plane figure is 360/n degrees, in this case 51.29 degreesImproved Answer:360/7 = 51.42857143 or 51.43 degrees to 2 decimal places.