let (2,-5) be P1 and (-1,-8) be P2 Slope is -5+8/2+1=3/3=1
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To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
Since the line is horizontal, the slope is zero.
1
The slope is the change in y divided by the change in x ("rise over run"). For the points (x1, y1) and (x2, y2), the slope calculation is: ( y1 - y2 ) ( x1 - x2 ) For the points (3, -9) and (7, 6), the slope calculation is: ( -9 - 6 ) = ( -15 ) = 3.75 ( 3 - 7 ) ( -4 )
First find the slope and then use the fact that y = mx+c where m is the slope and c is the intercept on the y axis to find the equation. Slope: -4 - -3 over -1 - -7 = -1/6 Equation: y = -1/6x -25/6 or 6y = -x -25