First find the slope and then use the fact that y = mx+c where m is the slope and c is the intercept on the y axis to find the equation.
Slope: -4 - -3 over -1 - -7 = -1/6
Equation: y = -1/6x -25/6 or 6y = -x -25
Points: (4, -2) and (6, -3) Slope: -1/2 Straight line equation: y = -1/2x There is no y intercept.
Diam refers to the length of a straight line connecting two points on the circumference of the circle and passing through the center.
Points: (-2.5, -0.5) and (4.5, -1) Slope: -1/14 Equation: 14y = -x-9.5 or x+14y+9.5 in its general form
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
They could be the coordinates of a straight line equation
y = 2.25x -6
2y+x+5 = 0
Y=4x+3
The general form is 11x - 10y + 19 = 0
If you mean points of (2, -3) and (4, 2) then the slope is 5/2 and the straight line equation is 2y = 5x-16
The equation is x = 2
If the line passing through these points is a straight line then it has a positive gradient.
Points: 0 2 and 6 0 Equation: y = -1/3x+2
The straight line equation works out as: y = 1/3x+7 So: k = 8
y = -1/14x-19/28 which can be expressed in the form of 2x+28y+19 = 0
x = 2
The formula for a line is: Y = mX + b