The second LARGEST? Is that correct? I think the second SMALLEST is a much more sensible question. How could you possibly know which is the LARGEST, much less the second largest? The SMALLEST is of course 1. Since 1^2 = 1, 1^3 = 1 and 1^5 = 1. The second SMALLEST I could find is 1073741824. I didn't try all possible numbers, but that was the second smallest I could find. 1024^2 = 1073741824, 32768^3 = 1073741824 and 64^5 = 1073741824. My initial gut was 64, but it isn't a perfect 5th, 2^5 = 32 NOT 64. Just try a couple 5th powers and see which are factorable (into a perfect square and a perfect cube). If you have a graphing calculator (or a computer) you can use the 3rd root and square root functions to do the math for you. But 64^5 was the smallest I could find (other than 1). Other numbers like 12^5, 24^5 and 32^5 did not work-out but 64 did. Hope this helps!
-- Find the square root of 4,321.-- It begins with 65.7...-- So the smallest perfect square greater than 4,321 must be (66)2.-- (66)2 = 4,356 .-- 4,356 - 4,321 = 35 .
It is 5.196*r^2 square units.
x + 2x = 6x = 180 9x = 180 9x/9 = 180/9 x = 20....theres you answer
Type your answer here... give the dimensions of the rectangle with an are of 100 square units and whole number side lengths that has the largest perimeter and the smallest perimeter
6.
Find the square root of the number.Take the integer part of the answer.Square the integer part.Subtract this square from the original number.
Try if you can find an integer that, when squared, gives you 80.
Try if you can find an integer which, when squared, gives you 31. If you can find it, 31 is a perfect square; otherwise, it isn't. Alternately, use your calculator to calculate the square root of 31. If you get an integer, it is a perfect square; otherwise, it isn't.
Start counting from ' 1 '. The first number you name that is a member of the set is the smallest integer in the set.
Immediate reaction is 2010, on the basis that if xy = x2 then x = y...
n=27
find the smallest number by which 9408 must be multiplied to get a perfect square/ also find the square of the number
0
Suppose the middle integer is 2a. Then the smallest is 2a-2 and the biggest is 2a+2. 4 times the smallest is 8a-8 So largest subtracted from the smallest is (8a-8) - (2a+2) = 6a-10 So, 6a-10 = 2*2a = 4a so that 2a = 10 So the integers are 8, 10 and 12.
3
The let statement is: let the smallest of the three integers be x.