40 degres
72
180-x= 2(90+x) - 60 180-x=180+2x - 60 -x=-60 x=60 Are you in my honors geometry class? The algebra is wrong. the third line should read -3x=-60 x=20 therefore the complement is 70o This agrees with the answer in the back of the book.
1st angle = 30 degrees 2nd angle = 60 degrees
a + b = 90, ie a = 90 - b;a = 2b - 36 so 2b - 36 = 90 - b ie 3b = 126 so b = 42 and a = 48 (which is 36 less than 84)
The complement is 60 degrees.
40 degres
60 degrees.
The supplement of A is 180 - A The complement of A is 90 - A So, 180 - A = 2*(90 - A) + 20 or 180 - A = 180 - 2A + 20 So A = 20 degrees
the answer is twice. the angle of rotation is twice the measure
Suppose the supplement of the angle is x degrees. Then the angle is 180 - x degrees. Therefore the complement of the angle is 90 - (180 - x) degrees = x - 90 degrees. So 5*(x - 90) - 2*x = 40 Solve the above equation for x.
The angle is 20 degrees
Angle is x degrees. Then 2(180 - x) = 5(90 - x) + 30 360 - 2x = 450 - 5x + 30 3x = 120 x = 40 Check: supplement is 140, 2 x 140 = 280 complement is 50, 5 x 50 = 250 difference is 30 as required. QED
Complimentary angles are two angles that add up to 90o. It the sum of two angles is 90o, and one is twice as big as the other, then we can make up a little equation to solve for that larger angle (a). It might look like this: 90o = a + ( a / 2 ) As our larger angle (a) was said to be twice as large as our smaller angle, our smaller angle (a/2) is half as large as the larger angle. 90o = 3a / 2 180o = 3a a = 180o / 3 = 60o Our mystery angle is a 60o angle. The smaller one is 30o. The larger angle is twice the smaller, and they two sum to 90o. Our work checks.
72
116 degrees
90 and 56