V = 4/3(Pi*r3): A sphere with a radius of 16 units has a volume of ≅17,157.28 cubic units.
V = 4/3(PI*73) ≅ 1,436.76 units3
4/3*pi*radius3 = 523.6 Making the radius the subject of the above gives it a value of 5.000003897 or about 5 cm
Volume in cubic units = 4/3*pi*153
Area = 4*pi*r^2
Volume = 4/3*pi*53 = 523.599 cubic units rounded to 3 decimal places
Surface area of a sphere: 4*pi*r^2
The area of a circle is given by the formula A = πr^2, where A represents the area and r represents the radius. Plugging in the given radius of 6.2 into the formula, we have A = π(6.2)^2. Evaluating this expression gives an area of approximately 120.79 square units.
The radius of a circle with a circumference of 1000m is approximately 159.15 meters. This can be found using the formula C = 2πr, where C is the circumference and r is the radius. Rearranging the formula to solve for r gives r = C / (2π). Substituting the given circumference into the formula will give you the radius.
4/3 pie(7exponent3)
The volume of a sphere is given by the formula V = (4/3)πr^3, where r is the radius. The radius of a 20 mm diameter ball is 10 mm (half of the diameter), which is 1 cm or 0.3937 inches. Plugging this into the formula gives V = (4/3)π(0.3937)^3 ≈ 0.209 cu inches.
V = 4/3(Pi*r3): A sphere with a radius of 16 units has a volume of ≅17,157.28 cubic units.
Diameter: 41/pi = 13 inches rounded to a whole number Radius: 13/2 = 6.5 inches Surface area of the sphere: 4*pi*6.5 squared = 530.929 square inches to three decimal places
( The volume of a sphere is (4/3)(pi)r3 ). The short answer: because of calculus. The long answer: This can be seen by using calculus to derive the volume of a sphere from the formula from it's surface area. To do this, we imagine that the sphere is full of infinity thin spheres inside it (all centered at the big sphere's center), and add up the surface areas of all the spheres inside. The formula for the surface area of a sphere is 4(pi)r2. Let's call R the radius of the big sphere we want to find the volume of. To find the volume of this sphere, we add up the surface areas of all the spheres whose radii range from 0 to R. This gives the following formula (where r is the radius of each little sphere): 0R∫ 4(pi)r2dr The 4 and pi can be factored out giving: 4(pi) (0R∫r2dr) Integrating gives: 4(pi) [r3/3]0R This is where the three comes from. Finishing the evaluation of the integral gives: 4(pi)(R3/3 - 03/3) = 4(pi)(R3/3) Which can be rewritten as (4/3)pi(R3) which is the formula for the volume of a sphere.
Using the formula for the volume of a cylinder (V = πr^2h), and substituting the given values, we can find the radius. Rearranging the formula to solve for the radius gives us r = √(V / (πh)). Plugging in the values, we get the radius as √(146 / (10π)) ≈ 2.15 inches.
(4/3) x (pi) x (17)3
V = 4/3(PI*73) ≅ 1,436.76 units3