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In the figure is parallel to . The length of is 2 cm the length of is 18 cm the length of is 27 cm. What is the length of?
If you mean an isosceles trapezoid with parallel sides of 18 cm and 27 cm then the length of the 4th sides is 2 cm
How do you convert height in cm?
one cm is 1/100th of a meter. if you have a length in cm then multiply it by 10^-2 to get the length in m. if you have the length in meters then multiply it by 10^2 to get the length in cm
What is the length of a rectangle if its width is 10 cm and its perimeter is 44 cm?
Its length is 12 cm because 2(12+10) = 44 cm
The length of a rectangle is twice the width the area is 72 square centimeters what is the length?
The width is 6 cm and the length is 12 cm.
What are the length and width of a rectangle if the length is three times longer than the width and the area is 48 sq cm?
The length is 12 cm and the width is 4 cm and so 12*4 = 48 square cm
When an object 5.0 cm tall is placed 12 cm from a converging lens an image is formed on the same side of the lens as the object but the image is 61 cm away from the lens. What is the focal length of t?
The image distance (61 cm) is positive since the image is on the same side of the lens as the object. Using the lens formula (1/f = 1/d_o + 1/d_i), where d_o is the object distance (12 cm) and d_i is the image distance, the focal length (f) of the lens is approximately 15 cm.
A pencil is located 20 cm from a concave lens with a focal length of 30 cm What is the image located?
virtual -12 enlarged
The object distance for a convex lens is 20.0 cm and the image distance is 4.0 cm The height of the object is 10.0 cm What is the height of the image?
Using the lens formula (1/f = 1/do + 1/di), where f is the focal length, do is the object distance, and di is the image distance, we can solve for f. Once we have the focal length, we can use the magnification equation (magnification = hi/ho = -di/do) to find the height of the image where hi is the height of the image and ho is the height of the object.
What is the scale factor of a dilation whose pre-image has a side of length 3 cm and whose corresponding side on the image is 1 cm?
1/31/31/31/3
An object is placed in front of a converging lens in such a position that the lens f 14.0 cm creates a real image located 27.0 cm from the lens Then with the object remaining in place the lens?
if ur asking what is the position of the object, you can use this formulas 1/f = 1/di + 1/do f: Focul length (14 cm) di: Image Distance (27 cm) do: Object distance (?) Object Distance ( do) = 4.69 cm
Light from a star is collected by a concave mirror How far from the mirror is the image of the star if the radius of curvature is 150 cm?
The image of the star will be 67.5 cm from the mirror because focal length is the raidus of curvature multiplied by 2 or (2)(C). So, therefore, 150 / 2 will give the focal length which would also be the answer.
What is the focal length of a converging lens which produces a virtual image four time the size of the object the image being 15 cm from the lens?
Using the lens formula (1/f = 1/do + 1/di) and the magnification formula (m = -di/do) where m = -4, you can solve for the focal length (f). Given the object distance (do = -15 cm), you can calculate the focal length to be 10 cm.
An object is placed at a distance of 50 cms from a convex lens of focal length 20cms then find the nature and position of the image?
Since the object is placed beyond the focal length of the convex lens (50 cm > 20 cm), the image will be real, inverted, and formed between the focal point and twice the focal length on the opposite side of the lens. The position of the image can be calculated using the lens formula: 1/f = 1/v - 1/u, where f is the focal length of the lens, v is the image distance, and u is the object distance.
In the figure is parallel to . The length of is 2 cm the length of is 18 cm the length of is 27 cm. What is the length of?
If you mean an isosceles trapezoid with parallel sides of 18 cm and 27 cm then the length of the 4th sides is 2 cm
A convex lens forms a real and inverted image of a needle at a distance of 50cm from the lensWhere is the needle placed in front of the convex lens so that the image is of the same size as the object?
A convex lens forms a real and inverted image of equal size only when it is kept at the center of curvature of the lens. The image is also formed at the center of curvature at the other side. Hence, the distance of object = distance of image = 50 cm. Now, focal length = � � radius of curvature = � � 50 cm = 25 cm Hope it is clear!
An object 2.5 cm long is placed on the axis of a concave mirror on 30 cm radius of curvature at a distance of 10 cm away from it Find the position size and nature of the image formed?
The mirror equation for concave mirrors is 1/f = 1/do + 1/di, where f is the focal length, do is the object distance, and di is the image distance. Since the object distance is 10 cm from the mirror and the radius of curvature is 30 cm, the focal length (f) is half the radius of curvature, which is 15 cm. Substituting the values, you can find the image distance (di) which is -20 cm (negative indicates a real image). The magnification can be calculated using M = -di/do, which in this case is -20/-10 = 2. This means the image is inverted and magnified by a factor of 2, located at a distance of 20 cm on the same side as the object from the mirror.
What is the focal length of a concave mirror that forms an image 25 cm from the mirror if the object distance is 20 cm?
1/o + 1/i = 1/ff = (o x i)/(o + i)f = 11.1 cm (rounded)
