2 ft^3 lets say that the volume is 1 ft x 1 ft x 2 ft
the area of one side 1 ft x 2 ft = 2 ft^2
the area of one end is 1 ft x 1 ft = 1 ft^2
4 sides
2 + 2 + 2 +2
2 ends
1 + 1
would give a surface area of 10 square feet. The question is does this change if the volume is shaped like a cylinder or a sphere etc?
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12 in = 1 ftradius = diameter ÷ 2Assuming those are internal dimensions, the volume of the pool is:volume = π x radius2 x depth= π x (12 ft ÷ 2)2 x (30 ÷ 12) ft= 90π cu ft≈ 282.74 cu ftConversion to gallons depends upon which gallon you're using:1 cu ft ≈ 6.23 imperial gallons → 282.74 cu ft ≈ 1761.16 imp gallons1 cu ft ≈ 7.48 US gallons → 282.74 cu ft ≈ 2115.07 US gallons
volume_cuboid = length × width × height = 4 ft × 2.3 ft × 5 ft = 46 cu ft surface_area_cuboid = 2 × (length × width + width × height + height × length) = 2 × (4 ft × 2.3 ft + 2.3 ft × 5 ft + 5 ft × 4 ft) = 2 × (9.2 sq ft + 11.5 sq ft + 20 sq ft) = 2 × 40.7 sq ft = 81.4 sq ft
I need one and a haft yards of sand. If the bags hold 2 cu feet how many bags do I need
1. A circle can't be "8 ft x 30 inches". The length and width of a circle are the same, by definition. 2. The area of a circle would be in square feet, but not in cubic feet.
288 sq inches... or an area 1ft x 2ft It's roughly 2 sq ft