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How can you find the area of a 30-60-90 triangle with a hypotenuse of 16?
Wiki User
∙ 11y ago
Using trigonometry.
Hypotenuse = 16
So shorter leg = 16*sin(30) = 16*1/2 = 8
Longer leg = sqrt(162 - 82) = sqrt(192) = 8*sqrt(3) = 13.86 approx.
Then Area = 1/2*legs = 1/2*8*13.86 = 55.43 square units.
Using trigonometry.
Hypotenuse = 16
So shorter leg = 16*sin(30) = 16*1/2 = 8
Longer leg = sqrt(162 - 82) = sqrt(192) = 8*sqrt(3) = 13.86 approx.
Then Area = 1/2*legs = 1/2*8*13.86 = 55.43 square units.
Using trigonometry.
Hypotenuse = 16
So shorter leg = 16*sin(30) = 16*1/2 = 8
Longer leg = sqrt(162 - 82) = sqrt(192) = 8*sqrt(3) = 13.86 approx.
Then Area = 1/2*legs = 1/2*8*13.86 = 55.43 square units.
Using trigonometry.
Hypotenuse = 16
So shorter leg = 16*sin(30) = 16*1/2 = 8
Longer leg = sqrt(162 - 82) = sqrt(192) = 8*sqrt(3) = 13.86 approx.
Then Area = 1/2*legs = 1/2*8*13.86 = 55.43 square units.
Wiki User
∙ 11y ago
Wiki User
∙ 11y agoUsing trigonometry.
Hypotenuse = 16
So shorter leg = 16*sin(30) = 16*1/2 = 8
Longer leg = sqrt(162 - 82) = sqrt(192) = 8*sqrt(3) = 13.86 approx.
Then Area = 1/2*legs = 1/2*8*13.86 = 55.43 square units.
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