Area of equilateral triangle: 0.5*7*7*sin(60 degrees) = 21.2 square inches
area = 1/2*base*perpendicular height =1/2*21*8 =84 square inches
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).
Since the formula for the area of a triangle is: A = .5 x h x b just go 63 = .5 x b x 18 then 63 = 9b 7 = b
To find the area of a square, you multiply the length of one side by itself. In this case, if the sides are 6 inches long, the area would be 6 inches * 6 inches = 36 square inches.
Area of the triangle: 0.5*16*14 = 112 square inches
Area of a triangle = 1/2*base*height Use Pythagoras to find the height which is 7.794228634 inches Area = 1/2*9*7.794228634 = 35.07402885 square inches Answer: 35 square inches to the nearest square inch.
Area of equilateral triangle: 0.5*7*7*sin(60 degrees) = 21.2 square inches
The dimensions are: altitude 12 inches and base 7 inches Check: 0.5*12*7 = 42 square inches
The formula to calculate the area of a triangle is (base/2) x height... therefore the are of the triangle in this case is 18 square inches
First rearrange Pythagoras' Theorem equation to find the height of the triangle in order to find the area: Height2 = hypotenuse2-base2. Height2 = 52-32. Height2 = 16. Height after square rooting both sides of the equation = 4. Area of a triangle = base*height/2 = 3*4/2 = 6 square inches. Therefore the area of a right angled triangle with dimensions in inches of III by IV by V is VI square inches. David Gambell, Merseyside, England.
The formula for finding the area of a triangle is: Area = 1/2*height*base in square units. Therfore substituting the values into the formula we have: 70 = 1/2*height*7 Rearranging the formula to find the height gives us: height = 70*2/7 = 20 inches. Therefore the height of the triangle is 20 inches.
36 square inches is the area.
area = 1/2*base*perpendicular height =1/2*21*8 =84 square inches
XXVII = 27 An equilateral triangle with a perimeter of 27 inches has three equal sides of 9 inches. Area of a triangle = base times its perpendicular height divided by 2. An equilateral triangle can be considered as being two right angled triangles joined together. So by halving the length of the base we can find its height by using Pythagoras' Theorem: hypotenuse2 - base2 = height2 92-4.52 = 60.75 square inches. Square root of 60.75 = 7.794228634 inches. Area = 9x7.794228634/2 = 35.07402885 square inches. Therefore area of an equilateral triangle with a perimeter of 27 inches is 35.074 square inches correct to 3 decimal places. Answered by David Gambell, Merseyside, England.
The area is 144 square inches.
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).