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Find the area of an equilateral triangle that has a perimeter of 21 inches. round the answer to one decimal?
Area of equilateral triangle: 0.5*7*7*sin(60 degrees) = 21.2 square inches
How do you find the area of a triangle with base 21 inche and height 8 inches?
area = 1/2*base*perpendicular height =1/2*21*8 =84 square inches
The height of a triangle is four times the length of the base find the base and height of the triangle if the base is 18 square inches?
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).
The height of a triangle is 18 inches Find the length of the base if the area of the triangle is 63 square inches?
Since the formula for the area of a triangle is: A = .5 x h x b just go 63 = .5 x b x 18 then 63 = 9b 7 = b
What is the area of a square if the sides are 6 inches long?
To find the area of a square, you multiply the length of one side by itself. In this case, if the sides are 6 inches long, the area would be 6 inches * 6 inches = 36 square inches.
