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-- Measure the length of the base, in inches.
-- Measure the height of the triangle, in inches.
-- Multiply the two numbers and take 1/2 of the product.
1/2 of the product is the area of the triangle, in square inches.
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Find the area of an equilateral triangle that has a perimeter of 21 inches. round the answer to one decimal?
Area of equilateral triangle: 0.5*7*7*sin(60 degrees) = 21.2 square inches
How do you find the area of a triangle with base 21 inche and height 8 inches?
area = 1/2*base*perpendicular height =1/2*21*8 =84 square inches
The height of a triangle is four times the length of the base find the base and height of the triangle if the base is 18 square inches?
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).
The height of a triangle is 18 inches Find the length of the base if the area of the triangle is 63 square inches?
Since the formula for the area of a triangle is: A = .5 x h x b just go 63 = .5 x b x 18 then 63 = 9b 7 = b
Now find square inches the area of the larger pizza in 12 inches and 14 inches?
NO.
Find the area L 16 in H 14 in in a triangle?
Area of the triangle: 0.5*16*14 = 112 square inches
If an equilateral triangle measures 9 inches on each side what is the perimeter?
Area of a triangle = 1/2*base*height Use Pythagoras to find the height which is 7.794228634 inches Area = 1/2*9*7.794228634 = 35.07402885 square inches Answer: 35 square inches to the nearest square inch.
Find the area of an equilateral triangle that has a perimeter of 21 inches. round the answer to one decimal?
Area of equilateral triangle: 0.5*7*7*sin(60 degrees) = 21.2 square inches
The altitude of a triangle is 5 inches less than its base. the area of the triangle is 42 square inches . find its base and altitude?
The dimensions are: altitude 12 inches and base 7 inches Check: 0.5*12*7 = 42 square inches
Find the area of an equilateral triangle with the given measurement six inch side?
The formula to calculate the area of a triangle is (base/2) x height... therefore the are of the triangle in this case is 18 square inches
Explain how can you calculate the area of a right angled triangle with a base of III inches and a hypotenuse of V inches giving an exact answer in Roman numerals?
First rearrange Pythagoras' Theorem equation to find the height of the triangle in order to find the area: Height2 = hypotenuse2-base2. Height2 = 52-32. Height2 = 16. Height after square rooting both sides of the equation = 4. Area of a triangle = base*height/2 = 3*4/2 = 6 square inches. Therefore the area of a right angled triangle with dimensions in inches of III by IV by V is VI square inches. David Gambell, Merseyside, England.
What is the height of the triangle with an area of 70 square inches and a base of 7 inches?
The formula for finding the area of a triangle is: Area = 1/2*height*base in square units. Therfore substituting the values into the formula we have: 70 = 1/2*height*7 Rearranging the formula to find the height gives us: height = 70*2/7 = 20 inches. Therefore the height of the triangle is 20 inches.
How do you find the area of a rectangle that is 36 square inches?
36 square inches is the area.
How do you find the area of a triangle with base 21 inche and height 8 inches?
area = 1/2*base*perpendicular height =1/2*21*8 =84 square inches
Can you work out the area of an equilateral triangle with a perimeter of XXVII inches giving details of your work?
XXVII = 27 An equilateral triangle with a perimeter of 27 inches has three equal sides of 9 inches. Area of a triangle = base times its perpendicular height divided by 2. An equilateral triangle can be considered as being two right angled triangles joined together. So by halving the length of the base we can find its height by using Pythagoras' Theorem: hypotenuse2 - base2 = height2 92-4.52 = 60.75 square inches. Square root of 60.75 = 7.794228634 inches. Area = 9x7.794228634/2 = 35.07402885 square inches. Therefore area of an equilateral triangle with a perimeter of 27 inches is 35.074 square inches correct to 3 decimal places. Answered by David Gambell, Merseyside, England.
Find the area of a square if a side measures 12 inches?
The area is 144 square inches.
The height of a triangle is four times the length of the base find the base and height of the triangle if the base is 18 square inches?
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).
