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If a property has an area of 920 square yards with a 40 foot frontage What is the depth of the lot?
621 ft looks wrong... its 207 ft An re test question gave the answer as: We know the total square yardage as well as the frontage expressed in feet. Since area is a function of length times width, and since there are 9 square feet in each square yard, we know that 40 times X divided by 9 will give us our answer. To make the calculation, multiplying 920 yards by 9 will allow us to divide the result by 40 to find the depth, which is 207 feet.
The width of a rectangle measures 4 cm less than the length What is the area of the rectangle if it's perimeter is equal to 100cm?
Let X represent the length, then X-4 represents the width. Perimeter of the rectangle is length plus width multiplied by two. Hence, 2(X + X - 4) = 100; 4X - 8 = 100; 4X = 108; X = 27. The length is 27 mm and the width is 27 - 4 = 23 mm. width = w length = w + 4 perimeter = w + w + w + 4 + w + 4 = 100 4w + 8 = 100 4w = 92 w = 23 width = 23 length = 27 area = 23 x 27 = 621
