With the distance formula.
Call the points A, B, and C. Call the sides ab, bc, and ca.
If we know where points A and B are, we can figure out the location of point C.
We use two distance formulas. The length of cb and the location of B will give us a set of points an equal distance from point B (a circle with center at B). The length of ca and the location of A will give us a set of points an equal distance from point A (a circle with center at A).
The intersection of these two sets (set the distance formulas equal to each other, or otherwise solve for the solution of a set of equations) will be the two possibilities of the vertex C.
The coordinates are the vertices of a triangle since they form three points.
It is the point (-2, -3).
If the coordinates of the three vertices are A = (p, s) B = (q, t) and R = (r, u) then centroid, G = [(p+q+r)/3, (s+t+u)/3].
I really don't know
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That depends on where the triangle ABC is located on the Cartesian plane for the coordinates of its vertices to be determined.
If by sperical triangle you mean a triangle on the surface of a sphere, you will need 3 dimensional coordinate geometry. Whether you use polar coordinates or linear coordinates will depend on what you want to "solve".
With a protractor or use trigonometry if you know its dimensions
With a protractor or use trigonometry if you know its dimensions
From geometry, we know that it is possible to calculate unknown lengths and angles of a triangle given particular information regarding the other angles and lengths of the sides of a triangle. For example, given beginning coordinates such as (x,y) in plane coordinates or the latitude and longitude, it is then possible to calculate new coordinates by measuring certain angles and distances (lengths of sides of a triangle).
The given coordinates when plotted and joined together on the Cartesian plane appears to form a scalene triangle.
If you mean: 2x+3y = 6 then the coordinates are (3, 0) and (0, 2) giving the triangle an area of 3 square units
The x-coordinate of the centroid is the arithmetic mean of the x-coordinates of the three vertices. And likewise, the y-coordinate of the centroid is the arithmetic mean of the y-coordinates of the three vertices. Thus, if A = (x1, y1), B = (x2, y2) and C = (x3, y3) then the coordinates of the centroid, G = [(x1,+ x2 + x3)/3, (y1 + y2 + y3)/3].
If the coordinates of the three vertices are (xa, ya), xb, yb) and (xc, yc) then the coordinates of the centroid are [(xa+xb+xc)/3, (ya+yb+yc)/3].
you cant
(1, -2)
(2, -3)